-
DOS下dir功能的模拟及扩充
DOS下dir功能的模拟及扩充-DOS the dir function simulation and expands
- 2022-01-21 01:35:14下载
- 积分：1
-
Java结合JSP的论坛系统！
Java结合JSP的论坛系统！-forum system.
- 2022-02-16 09:14:34下载
- 积分：1
-
将笛卡尔坐标系上的点定义为一个服务类Point，Point类提供求得坐标系上两点间距离的功能、获取和设置坐标的功能、获取极坐标的功能，和完成对已创建的Point...
将笛卡尔坐标系上的点定义为一个服务类Point，Point类提供求得坐标系上两点间距离的功能、获取和设置坐标的功能、获取极坐标的功能，和完成对已创建的Point类对象统计功能。设计测试Point服务类的应用程序主类，测试并显示输出提供功能的结果。(求以点(1,1)为极坐标原点，点(5,5)的极坐标)-Will be a point on the Cartesian coordinate system is defined as a service class Point, Point class provides coordinates obtained on the function of the distance between two points, access and set coordinates, polar coordinates to obtain functions, and the completion of the Point that have been created class object statistical functions. Design Test Point service class application" s main class to provide functionality to test and display the output results. (Seeking to point (1,1) to polar coordinates origin point (5,5) in polar coordinates)
- 2022-04-18 05:26:57下载
- 积分：1
-
ICcard
IC卡小读写工具,读写工具.相信对某些人有用的-ICcard
- 2022-05-07 05:14:02下载
- 积分：1
-
解决以下问题：
For solving the following problem:
"There is No Free Lunch"
Time Limit: 1 Second Memory Limit: 32768 KB
One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free.
However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
- 2022-12-06 21:00:03下载
- 积分：1
-
tidsp2407汇编程序例程，完整的源代码。
tidsp2407汇编程序例程，完整的源代码。-tidsp2407 assembler routines, complete source code.
- 2022-12-31 12:05:03下载
- 积分：1
-
去年的操作系统课程设计，模拟文件实现与设计系统
去年的操作系统课程设计，模拟文件实现与设计系统-last year"s courses on operating system design, simulation and documentation can be achieved Design System
- 2022-10-31 10:55:03下载
- 积分：1
-
淘宝网首页曾用的焦点图幻灯切换特效
淘宝网首页曾用的焦点图幻灯切换特效，代码中还给出了一些参数自定义选项，以便更好的查看效果。这款焦点图切换效果动画效果流畅，演示了横向水平切换和纵向垂直切换图片的方式，切换速度和停顿时间都可以自己调整，然后看效果，代码中有注释说明，非常方便调用。
- 2023-02-22 16:35:03下载
- 积分：1
-
经典的益智游戏，戒指，即时。几乎是这样的游戏。用以达到它。
经典的益智游戏，文曲星，快译通。。几乎此类游戏。用c去实现它。-classic puzzle games, rings, Instant. . Almost such games. C used to reach it.
- 2022-04-29 00:58:32下载
- 积分：1
-
effrc 是误差函数。 在计算二阶微分方程的时候会用到。
effrc 是误差函数。 在计算二阶微分方程的时候会用到。-effrc of error function. In calculating the second order differential equations are used.
- 2022-02-20 13:49:34下载
- 积分：1
