-
C wrote a small academic management system for others to write a curriculum desi...
用C写的一个小教务管理系统为别人写的一个课程设计-C wrote a small academic management system for others to write a curriculum design
- 2022-01-28 00:47:28下载
- 积分：1
-
休利特免费安装工具。简单而强大的支持pascal脚本，苏…
Inno Setup 是一款免费的安装制作工具。简洁而强大,支持 pascal 脚本,既有适合新手的脚本向导,也有适合高手的的脚本-Hewlett A free installation tools. Simple and powerful support pascal script, suitable for both novice script wizard, but also for experts in the script
- 2022-01-28 20:41:19下载
- 积分：1
-
Delphi教学管理系统(Access)
用DLEPHI+Access开发的教学管理系统，功能模块：数据更新、数据查询、统计表、密码管理等。主要是添加和修改教师、学生、教学情况的内容进行登记，并在以后方便查询，是一个资料维护系统。
- 2022-08-23 18:07:36下载
- 积分：1
-
这个机器人完全模拟人的操作，喜欢的朋友一起研究。 文件为jar包，内容完整。...
这个机器人完全模拟人的操作，喜欢的朋友一起研究。 文件为jar包，内容完整。-complete simulation of the robot"s operation, like the friends together. Documents jar package, the content is complete.
- 2023-02-09 09:50:04下载
- 积分：1
-
输入一系列递减顺序的整数（100,50,40,30……），以0标志结束，将这些数作为data域逆序建立一个单链表；从键盘输入一个整数X，将X插入到此单链表中并保...
输入一系列递减顺序的整数（100,50,40,30……），以0标志结束，将这些数作为data域逆序建立一个单链表；从键盘输入一个整数X，将X插入到此单链表中并保持单链表data域的值递增关系，输出此时单链表各结点data域的值；从键盘输入一个整数Y，若Y值在单链表中存在，则删除data域的值为Y的结点（注单链表中没有data域值相同的结点），并输出此时单链表各结点data域的值。-importation of a series of descending order of the integers (100,50,40,30 ...), to mark the end of 0, As several of these data to establish a domain reversal single-linked list; Keyboard input from an integer X, That will insert the single X-linked lists and maintain single-chain data domain increases the value, At this time the output of the single-linked list node data domain value; Keyboard input from an integer Y, if Y value in a single linked list exists, delete data domain is the value of Y node (single-chain data domain is not the same value nodes), At this point and the output of the single-linked list node data domain values.
- 2022-07-08 15:03:43下载
- 积分：1
-
write Java intellectual puzzles wrenched mobile phone game is based on Midp 2.0
Java写的智力拼图扳手机游戏，是基于Midp 2.0的-write Java intellectual puzzles wrenched mobile phone game is based on Midp 2.0
- 2022-01-25 18:50:01下载
- 积分：1
-
netwo
牛顿插值计算 牛顿插值计算 牛顿插值计算 牛顿插值计算 牛顿插值计算 -netwo
- 2022-03-02 02:57:01下载
- 积分：1
-
Realize this procedure three Ogre and three missionaries across the river, which...
此程序实现了三个食人魔和三个传教士的过河问题，其中船上最多只能载两个人，船上和两岸的传教士数大于食人魔数传教士才是安全的-Realize this procedure three Ogre and three missionaries across the river, which can only be set on board a maximum of two people on board and on both sides of Ogre missionaries more than a few missionaries are safe
- 2022-12-13 19:15:03下载
- 积分：1
-
穿口助手
穿口助手-Assistant to wear mouth
- 2022-02-15 10:21:28下载
- 积分：1
-
Bus labviewCAN the basis of examples of the use of exercises, is the basis of La...
labviewCAN总线使用的基础实例练习，是初学labview的基础。-Bus labviewCAN the basis of examples of the use of exercises, is the basis of LabVIEW beginner.
- 2022-06-19 11:50:08下载
- 积分：1
