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ROBODoc通过提取源码中的特定格式的注释块(specially formatted headers)并形成文档文件,文档文件的格式包括HTML, ASCII...
ROBODoc通过提取源码中的特定格式的注释块(specially formatted headers)并形成文档文件,文档文件的格式包括HTML, ASCII, XML DocBook, LaTeX或RTF 还能间接形成PDF 和HTML Help文档-ROBODoc By extracting the source code of the specific format of the comment block (specially formatted headers) and the formation of the document file, document file formats, including HTML, ASCII, XML DocBook, LaTeX, or RTF also an indirect form PDF and HTML Help documentation
- 2022-03-18 10:42:30下载
- 积分:1
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tifftechnote2.txt.gz IJG的JPEG
ijg jpeg TIFFTechNote2.txt.gz
- 2022-02-12 15:29:03下载
- 积分:1
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卡尔加里地震研究人员自由软件大学
Univ. of Calgary CREWS的免费地震研究软件-Univ. Of Calgary CREWS seismic studies of the free software
- 2022-03-09 14:17:23下载
- 积分:1
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gis地图
gis地图 --- --æ–‡å—1-gis writing a map
- 2023-05-23 18:25:03下载
- 积分:1
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gtrack轨迹图的标题和显示鼠标的位置坐标。
GTRACK Track mouse position and show coordinates in figure title.
Once GTRACK is active the mouse position is constantly tracked and printed on the current figure title. A left-click will print the coordinates in the command line and store them. Clicking the mouse right button deactivates GTRACK.
- 2022-01-22 13:54:01下载
- 积分:1
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提供矩阵以及向量的各种运算,线性方程组的求解,二次曲面的插值和逼近,最小二乘法等数值分析计算工具
提供矩阵以及向量的各种运算,线性方程组的求解,二次曲面的插值和逼近,最小二乘法等数值分析计算工具-Provide a variety of matrix and vector operations, linear equations, quadratic surface interpolation and approximation, the least square method such as numerical analysis and calculation tools
- 2022-05-09 09:16:49下载
- 积分:1
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遗传算法求函数最优解
遗传算法求解函数的最大值,且函数只有一个变量。求函数f(x)=x+10*sin(5x)+7*cos(4x),x∈[0,9]。染色体长度为20,交叉概率为0.95,变异概率为0.08,迭代次数为25。 程序修改后可以用于多参数函数的求解。
- 2022-07-16 21:22:56下载
- 积分:1
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游戏逻辑是用python实现的,底层用D3D绘制。对于初学D3D与python的朋友有帮助,其中还有从C++扩展python的方法。...
游戏逻辑是用python实现的,底层用D3D绘制。对于初学D3D与python的朋友有帮助,其中还有从C++扩展python的方法。-Game logic is to use python to achieve, the underlying mapping using D3D. D3D and python for beginner friends have to help, including from the C++ Expansion python method.
- 2022-01-21 05:03:50下载
- 积分:1
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游戏规则
目的:在本游戏中,你将作为一名裁缝,将尽可能多的纽扣穿成
一个闭合的路线。游戏初始有 15 个纽扣,随着时间的增
加,纽扣数目...
游戏规则
目的:在本游戏中,你将作为一名裁缝,将尽可能多的纽扣穿成
一个闭合的路线。游戏初始有 15 个纽扣,随着时间的增
加,纽扣数目也增加,当达到70个时游戏即结束。
规则:只能在有纽扣的点穿线,且只能在水平方向或竖直方向穿
线。线可交叉,但有纽扣的点不能交叉连接。
秘诀:要尽可能使连线长且该连线上的纽扣数多。-purpose of the rules of the game : In the game, you will act as a tailor, as much as a button to wear closed routes. Initial games are 15 buttons, with the increase in time, increase the number of buttons, reached 70 at the end of that game. Rules : only when there is the point of threading button, and then only in the horizontal direction or vertical direction of threading. Cross-line, but the point Button can cross-connect. The secret : To the extent possible, but the long-line connections on the button a few more.
- 2022-07-08 05:58:19下载
- 积分:1
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用于正则表达式的C++库. 现在的版本那是2.6.4
用于正则表达式的C++库. 现在的版本那是2.6.4-Regular expressions are used in the C++ library. The current version is 2.6.4
- 2023-02-07 04:05:03下载
- 积分:1