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liushuideng
真正的流水灯：（1）第1，3，5，7个灯半亮，其余的全亮。
（2）第1个亮1/8,第2个亮2/8,第3个亮3/8,第4个亮4/8,第5个亮5/8,第6个亮6/8,第7个亮7/8,第8个全亮。
（3）来点小难的，所有的灯逐渐从暗到全亮，再由全亮到暗。
（4）最难的：8个灯从第一个开始依次渐亮，直到最后一个。再从最后一个起渐暗，直到第一个。如此循环往复。这才是真正的流水灯。
(The real light of the water: (1), paragraphs 1, 3, 5, 7 semi-bright lights, the rest of the bright. (2) a bright 1/8, 2 bright 2/8, 3 bright 3/8, 4 bright 4/8, 5 bright 5/8, 6 bright 6/8 7 bright 7/8, 8 full-bright. (3) to a little difficult, all the lights gradually from dark to full brightness, and then from full bright to dark. (4) the hardest: 8 light from the first start in turn gradually brighter, until the last one. From the last one from the dark, until the first. So on ad infinitum. This is true of light water.)
- 2012-05-19 12:03:12下载
- 积分：1
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asp.net
微信公众号程序实例，查询公交，火车，飞机等。有详细的注释。asp.net4.0环境。(Procedural micro-channel public inquiries, public transport, trains, planes and so on. There are detailed notes. asp.net4.0 environment.)
- 2020-06-30 00:00:02下载
- 积分：1
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fiujai-V7.1
小波包分析提取振动信号中的特征频率，分析了该信号的时域、频域、倒谱，循环谱等,有井曲线作为输入可计算其地震波的衰减。( Wavelet packet analysis to extract vibration signal characteristic frequency, Analysis of the signal time domain, frequency domain, cepstrum, cyclic spectrum, etc. There is a well attenuation curve as input to calculate its seismic waves.)
- 2017-05-09 20:23:34下载
- 积分：1
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Hydrangeas - 副本
图片展示,一个很不错的图片展示嘿嘿嘿。。。(Picture show, a very good picture show hey hey hey.)
- 2018-03-03 17:28:26下载
- 积分：1
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CRC 通讯常用校验码计算方法
自己编写的一个计算通讯CRC校验的类，可直接饮用；
包含多达20种校验的方法；
- 2023-01-01 19:55:03下载
- 积分：1
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buckdanhuan
单环PID控制buck电路，控制器tms320f28335,通过改变占空比控制buck电路输出电压大小。(Single-loop PID control buck circuit, controller tms320f28335, by changing the duty cycle control buck circuit output voltage.)
- 2020-10-27 12:59:58下载
- 积分：1
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realnew4444
用real控件播放RM文件(play rm files by real controls)
- 2005-01-12 21:52:42下载
- 积分：1
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test
某公司收到若干报价，然后报价由低到高进行排序。设最低报价为F,最高报价为G。n=0.2*(G-F)
设A，B，C，D，E五个等距区间并取：
A=[F,F+n） B=[F+n,F+2n) C=[F+2n,F+3n) D=[F+3n,F+4n) E=[F+4n,G)
所有的报价都按各自的大小，分别列入上面五个区间。各自区间内的最小报价为该区间的代表报价。如果某区间内没有报价 则以小于该区间的且与该区间相邻的区间内的最高报价代表该区间报价，如果该区间与与之相邻的较小区间内都没有报价则该区间不参加最后计算。取各区间的代表值， 求出其平均值 做为评标基准报价
(A company received a number of quotations, and quotations from low to high order. Minimum price for the F, the highest offer for the G. n = 0.2* (GF) Let A, B, C, D, E, and five equidistant intervals obtained: A = [F, F+ n) B = [F+ n, F+2 n) C = [F+ 2n, F+3 n) D = [F+3 n, F+4 n) E = [F+4 n, G) All quotes are by their size, five were included in the above range. The minimum offer their own range representative of the range quoted. If a range does not offer less than the range of places and range of adjacent intervals with the highest offer within the offer on behalf of the interval, if the interval and the adjacent smaller range do not offer the range not to participate the final calculation. Take the representative value of each interval, calculate the average price as a benchmark evaluation)
- 2011-11-10 22:44:43下载
- 积分：1
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FOC 电机 控制例程
M4 做的FOC 电机控制 ,可以供大家参考使用！！
- 2022-08-07 22:56:20下载
- 积分：1
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Bitree
二叉树的打包数据结构，包括遍历，删除，添加，注释详细(Packaged binary tree data structure, including traversal, delete, add, annotate details)
- 2015-10-04 23:44:33下载
- 积分：1
