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这是一个可以在后台偷取你闪盘里所有资料的小软件。
只要你的闪盘一插上，所有的东东都被悄悄拷走.代码开放,可以热键呼出....
这是一个可以在后台偷取你闪盘里所有资料的小软件。
只要你的闪盘一插上，所有的东东都被悄悄拷走.代码开放,可以热键呼出.-This is a steal in the background you can flash all the information a small software. One of the key as long as you plug in, all the East have been quietly taking copy. Code open, you can hotkey exhaled.
- 2022-06-21 13:46:08下载
- 积分：1
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Kinect的手势跟踪SDK v.2.0
应用背景本项目 ；执行手指与Kinect V 2 跟踪方面；随着官方Kinect SDK V 2手指和手的跟踪包括在人机交互（HCI）领域的。这项工作的目的是描述一个强大的和有效的方法来跟踪方面，利用Kinect设备中实时的手指。关键技术Kinect V 2，V 2 ；Kinect SDK， ；人机交互（HCI）
- 2022-01-26 05:26:13下载
- 积分：1
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image to hex conversion
它用于将图像像素转换为文本文件中的十六进制值；
- 2022-07-26 12:36:26下载
- 积分：1
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有关指针的学习文档，包括普通指针、函数指针、数组指针等...
有关指针的学习文档，包括普通指针、函数指针、数组指针等-The indicators of learning documents, including the general pointers, function pointers, array pointers and so on
- 2022-12-16 01:40:03下载
- 积分：1
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CrossTheMaze
Assume that Edison has found himself in a square-shaped maze of NxN square cells which is surrounded by walls from the outside. In the maze, some of the cells are also walls. Edison can only move between two empty cells in four directions, north, south, west and east. In order to get out of the maze, he drafts a plan. He uses his left hand to lean on the wall and goes by following the wall.
Here is the question, is Edison able to get out of the maze in at most 10,000 steps? If he can make it, output the path. By getting out of the maze, he only needs to be in the exit cell. If the starting cell is the same as the exit, Edison won"t need to move and can directly get out of the maze.
Input
The first line of the input gives the number of test cases, T. T test cases follow. Each test case starts with an integer N. N is the size of the maze. Th
- 2022-02-25 06:08:30下载
- 积分：1
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D3D9黑屏优化-vs2010源码
可以用来优化游戏的CPU占用率，D3D9黑屏优化插件
- 2022-05-26 11:14:16下载
- 积分：1
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win32服务端socket封装
资源描述win32 API网络编程中比较麻烦，这里是封装好的socket类
- 2022-04-28 09:20:09下载
- 积分：1
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BP网络，解决人工智能中BP网络问题，是人工智能的大作业
BP网络，解决人工智能中BP网络问题，是人工智能的大作业-BP Net source code for AI
- 2023-03-31 00:25:03下载
- 积分：1
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建立交换文件的 C 语言源代码,对学习C语言有一定的帮助.
建立交换文件的 C 语言源代码,对学习C语言有一定的帮助. -Establishing an exchange of documents C language source code for learning C language certainly helps.
- 2023-03-13 07:15:03下载
- 积分：1
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矩阵乘法
此代码文件会计算任何两个矩阵相乘。矩阵可以是任意大小。它还检查乘法有效性条件。如果两个矩阵的乘法是不可能的情况下它会造成一个错误然后将需要来自用户的另一个矩阵。
- 2022-05-14 17:41:18下载
- 积分：1
