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随机有限元程序及算例,有学习价值,用FORTRAN语言写的
随机有限元程序及算例,有学习价值,用FORTRAN语言写的-Stochastic finite element program and example, have learning value, written in FORTRAN language
- 2023-04-07 05:50:04下载
- 积分:1
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labview程序编程技巧演示,用labview编写windows应用图像编程小程序...
labview程序编程技巧演示,用labview编写windows应用图像编程小程序-LabVIEW programming skills demonstration, prepared by LabVIEW image windows programming applet
- 2022-05-09 07:13:23下载
- 积分:1
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ads1115
ads1115历程以及最小系统
基于msp430(Course and schematic diagram of ads 1115
Based on MSP430)
- 2020-06-24 19:00:01下载
- 积分:1
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三线交错双向DCDCmatlab仿真
说明: 三相交错双向dcdc微电网的matlab仿真资料,仅供参考。(Matlab simulation data of three-phase staggered bidirectional DCDC microgrid are for reference only.)
- 2019-06-23 21:39:14下载
- 积分:1
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Classic Doger source code using Managed Directx realize very exciting, with the...
经典的Doger源代码 用Managed Directx实现 征得很精彩 有完整的光照,材质,还有优秀的游戏程序算法-Classic Doger source code using Managed Directx realize very exciting, with the consent of a complete light, texture, there are excellent game program algorithm
- 2023-02-27 20:00:03下载
- 积分:1
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前言
一个图书管理系统,实现浏览图书,图书借阅,图书归还的功能
环境是python3.7.3,Djiango2.2.2 mysql8.0(A library management system, the realization of browsing books, books borrowing, books back to the function
37/5000
The environment is python3.7.3, Djiango2.2.2 mysql8.0)
- 2019-06-26 22:45:10下载
- 积分:1
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VC++基于BMP图像生成不规则的程序窗口
VC++基于BMP图像生成不规则的程序窗口,这个不规则的窗体,有些部分是透明的,从外观形状来说,找不到任何规律,完全是奇特的形状,这个形状其实是来源自一张格式的位图,VC++将通过特殊的方法让窗体呈现出位图的形状,具体如何实现呢?请参考这个源码。
- 2022-04-23 14:48:15下载
- 积分:1
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CSS模板源代码。您可以使用此文件的源代码来创建你自己的…
CSS templates source codes. You can use this file souce codes to create your own menus.
- 2022-07-08 06:54:53下载
- 积分:1
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例题
说明: 初学随机过程在MATLAB仿真上会有不懂,关于谱密度的几个例题(Some examples about spectral density are not clear in MATLAB simulation of initial stochastic process.)
- 2020-06-24 19:20:02下载
- 积分:1
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22_deadlock
说明: 本例的源描述超过了演示版限制的300行,
如果您需要对其进行编译与模拟,请与北京理工大学
ASIC研究所联系,获取Talent系统的完全版本.
联系方法:
电话:010-68912434
(The source described in this case than the demo version of the 300 line limit, if you need to be compiled with the simulation, please contact ASIC Institute of Beijing Institute of Technology to obtain the complete version of Talent system. Contact: Tel :010-68912434)
- 2008-09-09 18:11:58下载
- 积分:1