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naca0012

于 2020-09-07 发布

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下载积分: 1 下载次数: 8

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代码说明：

说明：有限体积法,通过有限体积法求解naca0012流场，通过有限体积法求解naca0012流场(finite volume method)

文件列表：

naca0012, 0 , 2020-09-07
naca0012\Copy_2_of_dflux_.m, 2652 , 2020-08-23
naca0012\Copy_of_dflux_.m, 3552 , 2020-08-23
naca0012\Euler_IC2d.m, 1701 , 2018-05-30
naca0012\WENO5LF.m, 3722 , 2020-08-17
naca0012\WENO5LF2d.m, 1963 , 2020-08-17
naca0012\WENOcaller.m, 1554 , 2020-08-17
naca0012\d_.m, 1676 , 2020-08-25
naca0012\dflux.m, 3033 , 2020-08-23
naca0012\dflux1.m, 1934 , 2020-08-19
naca0012\dflux_.m, 1987 , 2020-09-07
naca0012\fdisplay.m, 160 , 2018-05-30
naca0012\flux2.m, 2985 , 2020-08-23
naca0012\flux_split.m, 1048 , 2020-08-23
naca0012\fs_vanl.m, 557 , 2020-08-24
naca0012\fs_vanl_.m, 960 , 2020-08-24
naca0012\geneg.m, 5453 , 2020-08-23
naca0012\ggg.m, 5515 , 2020-08-18
naca0012\main.m, 2281 , 2020-09-07
naca0012\mesh_axis.m, 559 , 2020-08-24
naca0012\n_grid.m, 1143 , 2020-09-07
naca0012\set_boundary.m, 2786 , 2020-08-23
naca0012\set_boundary_.m, 4072 , 2020-08-23
naca0012\test_routines.m, 521 , 2018-05-30

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programming-advanced-applications
matlab 学习技巧，现在把我用的，也就是对我帮助很大的留个文件传上去，希望对大家有用，第五高级编程应用(matlab learning skills, and now I use, which is a great help to me to leave a document passed up, we want to be useful, the fifth high-level application programming)

2013-08-24 11:57:26下载

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2012-01-19 23:40:57下载

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repval
repval(X) finds all repeated values for input X, and their attributes. (The input may be vector, matrix, char string, or cell of strings Y=repval(X) returns the repeated values of X [RV, NR, POS, IR]=repval(X) returns the following outputs RV : Repeated Values (sorted) NR : Number of times each RV was repeated POS : Position vector of X of RV entries IR : Index of repetition Example: X=[1 5 5 9 5 5 1] [RV,NR,POS,IR]=repval(X) Output: RV = [1 5] Numbers 1 and 5 are repeated values NR = [2 4] Respectively repeated 2 and 4 times POS = [1 7 2 3 5 6] Position index of X for repeated values IR = [1 1 2 2 2 2] Corresponding to which index of RV )

2010-12-14 15:13:45下载

积分：1

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