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这是我辛苦编的一个JAVA程序,是关于SocketClientprogram.简单,易懂.希望能被采用.多谢管理员过目....
这是我辛苦编的一个JAVA程序,是关于SocketClientprogram.简单,易懂.希望能被采用.多谢管理员过目.-This is the hard part I of a Java process on SocketClientprogram. simple. understandable. hope can be used. thank administrators read. Thank you
- 2022-01-28 17:39:21下载
- 积分:1
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PBEKey
The interface to a password-based-encryption key.
- 2014-06-02 00:09:09下载
- 积分:1
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Python3高级教程
讲解Python的基本使用方法,包括数据结构,生成器,迭代器和网络编程(Explain the basic usage of Python)
- 2020-06-23 22:40:01下载
- 积分:1
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本文介绍了WhoIS协议的实现,描述了如何通过编程查询WhoIS信息...
本文介绍了WhoIS协议的实现,描述了如何通过编程查询WhoIS信息-WhoIS the realization of the agreement, described how inquiries WhoIS Programming Information
- 2022-06-17 17:07:23下载
- 积分:1
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zoj1094
zoj094
Matrix multiplication problem is a typical example of dynamical programming.
Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose.
For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix.
There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C).
The first one takes 15000 elementary multiplications, but the second one only 3500.
Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy.
(Matrix multiplication problem is a typical example of dynamical programming.
Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose.
For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix.
There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C).
The first one takes 15000 elementary multiplications, but the second one only 3500.
Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy.
)
- 2012-06-10 10:38:53下载
- 积分:1
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cscms_v3.5.6_utf8
说明: web控制端,下载后看readme进行安装使用(english one two three four five six seven eight nine ten)
- 2020-06-23 22:40:01下载
- 积分:1
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lyvd_point
B curve left key point, right end vevr good(Curve B left key point, right end vevr good)
- 2017-05-09 15:10:32下载
- 积分:1
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PSOC_SLAVE_K60
Capsense source code
- 2013-12-21 23:32:18下载
- 积分:1
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RSS-Reader-Sample
Rss reader for a web design
- 2013-11-28 00:41:24下载
- 积分:1
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uniformcirclearray
阵元数16下均匀圆阵的零限形成,先建立约束函数,再创建目标函数,计算零陷(Element number 16 under the Uniform Circular Array of zero-threshold shape, to create constraint function, and then create the objective function, calculated Null)
- 2008-12-13 11:49:35下载
- 积分:1