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ACD_Models_FEX
matlab garch tool box.rarmatlab garch tool box.rarmatlab garch tool box.rar
- 2010-11-19 13:56:19下载
- 积分：1
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ACStraver
说明： 旅行商问题蚁群算法求解，不同的是需要设置文本文件的坐标。灵活性强，注释清晰。(Ant colony algorithm for traveling salesman problem, the difference is you need to set the coordinates of the text file. Flexibility, clear notes.
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- 2011-04-05 11:31:42下载
- 积分：1
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rivercon
一维水质模型，本程序研究一维河流的污染物扩散，短时间持续排放BOD的浓度变化规律
本程序采用中心隐式差分求解
问题t=0到t=1h偶然排放BOD 使河水断面L0=10mg/L河流平均速度5km/h
纵向弥散系数D=2km2/h BOD衰减系数k1=0.015h-1 解BOD浓度 L(x，t)(One-dimensional water quality model, the procedure of one-dimensional dispersion of pollutants in the river, a short continuous changes of the concentration of BOD emissions of the program implicit difference method with central issues t = 0 t = 1h accidental emissions to the BOD to the river section L0 = 10mg/L average speed of the river 5km/h vertical diffusion coefficient D = 2km2/h BOD decay coefficient k1 = 0.015h-1 Solution for BOD concentration L (x, t))
- 2020-12-04 16:49:23下载
- 积分：1
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mss32
最近在看hl2,发现mdl模型必须从36转到37,哈哈,恰好看到此贴,非常感谢。(recently watching hl2, mdl model must be found from 36 to 37, haha, just to see patch. Thank you very much.)
- 2007-02-03 22:38:59下载
- 积分：1
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bisect
二分法求解非线性方程的根，有详细中文注释和例程！(Dichotomy for solving nonlinear equations of the root, with detailed notes in Chinese and routines!)
- 2011-12-27 21:57:58下载
- 积分：1
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GaussianBeam1D
describe a gaussian beam 1D
- 2011-01-20 19:31:09下载
- 积分：1
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polardb
波束形成算法中一种变换形式的极坐标算法（与传统的极坐标算法不同）(Polardb is a modified version of the regular polar function.)
- 2012-04-23 11:27:59下载
- 积分：1
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myBurg
根据burg算法实现的AR模型功率谱计算(Burg algorithm AR Model Power spectrum calculation)
- 2012-08-01 22:06:42下载
- 积分：1
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DeepLearnToolbox-master
deeplearning的工具箱，里面包含了多种神经网络的模型(deeplearning toolbox, which contains a variety of neural network models)
- 2014-01-18 13:19:09下载
- 积分：1
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hypot
抛物线法求解
方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*.
设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程
例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式.
方程中的系数a0由你得到的根p*来确定.(parabolic equation method Construction Methods : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p*. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p* to determine.)
- 2014-04-25 08:18:59下载
- 积分：1
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