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SumRobustDiff
code to get optical flow using sum of robust differences method
- 2010-11-26 06:16:12下载
- 积分：1
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audio_watermarking_lowpassfilter_attack
apply a lowpass filter to a watermarked audio signal to test the robustness
input : vector representing the watermarked audio file
output : vector representing the watermarked audio file corrupted by a lowpass filter
- 2012-11-15 21:49:16下载
- 积分：1
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cSharp-v4.0
c# language specification book (zip version)(pdf inside)
- 2014-01-15 19:10:50下载
- 积分：1
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kalman(CPP_C_MATLAB)
卡尔曼滤波原理及程序手册，非常好用，非常方便(Kalman filtering principles and procedures manual, very easy to use, very convenient)
- 2013-03-24 10:43:52下载
- 积分：1
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min_dist
Computes the minimum distance between two different shape polygons. (Vertex-vertex case)
- 2011-01-16 01:54:51下载
- 积分：1
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hmodeinitial
加深对卡尔曼滤波算法的理解，了解卡尔曼滤波器算法的基本特点，掌握卡尔曼滤波算法应用研究的基本步骤和方法(deepen the Kalman filter algorithm understanding, knowledge Kalman Filter algorithm for the basic features, master Kalman filtering algorithm applied research on the basic steps and methods)
- 2007-01-13 22:51:35下载
- 积分：1
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nonlinear_project
simulation of IPMSM motor nonlinear control using sliding mode with application of matlab code programs
- 2014-08-26 18:47:04下载
- 积分：1
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Cap06_Shadowing-and-Multipath
This file is the programs of (chapter 6) of book (Modeling the Wireless Propagation Channel a Simulation Approach with MATLAB) which is related to shadowing and multupath. It helps you to simulate wireless channel.
- 2013-10-15 23:09:24下载
- 积分：1
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Hilbertputu
非平稳信号经过分解后，对其进行谱分析，此希尔伯特谱程序，弥补了了以前的缺陷(Non stationary signal through decomposition, the spectral analysis, the Hilbert spectrum procedures, make up for the previous defect)
- 2011-11-13 20:42:19下载
- 积分：1
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shuxuejianmo_3
说明： 某厂向用户提供发动机，合同规定，第一、二、三季度末分别交货40台、60台、80台．每季度的生产费用为 （元），其中x是该季生产的台数．若交货后有剩余，可用于下季度交货，但需支付存储费，每台每季度c元．已知工厂每季度最大生产能力为100台，第一季度开始时无存货，设a=50、b=0.2、c=4，问工厂应如何安排生产计划，才能既满足合同又使总费用最低．讨论a、b、c变化对计划的影响，并作出合理的解释(To provide users with a factory engine, contract, first, second and third quarter respectively, delivered at the end of 40, 60, 80. Quarterly cost of production (million), in which x is the quarter of the number of production. If the remaining after delivery, can be used for delivery next quarter, subject to payment of storage fees, for each element c of each quarter. The largest known plant production capacity of each quarter to 100, the beginning of the first quarter of stock, set up a = 50, b = 0.2, c = 4, asked how to arrange the production of the factory plans to meet the total cost of the contract makes the minimum . Discussion of a, b, c of the impact of change on the plan and make a reasonable explanation)
- 2009-07-24 22:58:49下载
- 积分：1
