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matrix
MATLAB矩阵函数教程，例子及简单应用，很实惠，适用初学者(MATLAB matrix functions tutorials, examples and simple applications, it is affordable, suitable for beginners)
- 2010-06-21 12:48:09下载
- 积分：1
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FD1D11
Question 1.1 Sullivan
- 2010-08-12 11:33:32下载
- 积分：1
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mchap8
MATLAB插值与数据拟合、样条插值与数值微积分、由已知数据拟合数学模型、信号分析与数字信号处理基础(MATLAB interpolation and data fitting, spline interpolation and numerical calculus, from the known data fitting mathematical model, signal analysis and digital signal processing-based)
- 2009-11-16 09:56:38下载
- 积分：1
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bpsksignalgen
说明： 共同学习，共同提高，资源共享
一个产生bpsk信号的例子，可以推出MPSK的调制基带信号(studying together, enhancing and sharing resources have BPSK signals an example, can be introduced MPSK the baseband signal modulation)
- 2006-03-18 11:32:03下载
- 积分：1
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power-systerm-in-matlab
电力系统的matlab/simulink仿真与应用(the application and simulation of power systerm in matlab/simulink)
- 2012-11-05 09:21:11下载
- 积分：1
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benqao_v28
包括回归分析和概率统计，是信号处理的基础，小波包分析提取振动信号中的特征频率。( Including regression analysis and probability and statistics, Is the basis of the signal processing, Wavelet packet analysis to extract vibration signal characteristic frequency.)
- 2016-12-16 07:52:49下载
- 积分：1
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BAS-PID
说明： 天牛须算法与pid控制算法结合，通过matlab实现，欢迎下载(Tianniu must algorithm and PID control algorithm, through MATLAB, welcome to download)
- 2021-01-11 10:51:26下载
- 积分：1
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HSFUN
说明： 函数进行格式分析,通过计算，形成结果输出，达到自动的目的(User c++ edit the text)
- 2009-08-02 06:25:18下载
- 积分：1
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icp
迭代最近点算法的完整Matlab程序，输入两个点集，输出旋转矩阵、平移向量和整体误差，验证可用。(Complete iterative closest point algorithm Matlab program, enter the two point sets, the output rotation matrix and translation vector and the overall error, verify availability.)
- 2020-11-04 16:09:51下载
- 积分：1
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hypot
说明： 抛物线法求解
方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*.
设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程
例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式.
方程中的系数a0由你得到的根p*来确定.
(parabolic equation method Construction Methods : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p*. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p* to determine.)
- 2005-12-03 18:19:16下载
- 积分：1
