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关于430的介绍，内含430的结构图，技术文章，工具，PCB原理图，及用户说明...
关于430的介绍，内含430的结构图，技术文章，工具，PCB原理图，及用户说明-On the 430
- 2023-01-28 17:35:13下载
- 积分：1
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matchman
火柴人对打游戏的文件配置,说明,源代码等等,内容非常丰富啊(Matches people fighting game configuration files, description, source code, etc., the content is very rich ah)
- 2007-09-17 21:11:43下载
- 积分：1
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layer
cad图层显示、关闭、冻结等快捷命令，非常好用(CAD layer display, close, freeze and other shortcut commands, very useful)
- 2020-06-21 17:20:01下载
- 积分：1
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LabView_EXE_SETUP
LabView在写完程序后需要打包封装，本文就是介绍如何实现的，在写完程序后如果要在其它没有装LabView软件的电脑上，可以参考本文。(LabView procedures need to be packed in the finished package, is how to achieve this, the finish procedure is not installed if you want to LabView software on other computers, you can refer to this article.)
- 2010-12-22 22:16:44下载
- 积分：1
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VGA_LCD 控制器IP,我也是从网上下载的，还没有来得及看，
VGA_LCD 控制器IP,我也是从网上下载的，还没有来得及看，-VGA_LCD controller IP, I also downloaded from the Internet, has not yet had time to look,
- 2023-03-06 18:30:03下载
- 积分：1
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遗传算法求解多旅行商问题
旅行商问题(TravelingSalesmanProblem，TSP)是一个经典的组合优化问题。经典的TSP可以描述为：一个商品推销员要去若干个城市推销商品，该推销员从一个城市出发，需要经过所有城市后，回到出发地。应如何选择行进路线，以使总的行程最短。从图论的角度来看，该问题实质是在一个带权完全无向图中，找一个权值最小的Hamilton回路。由于该问题的可行解是所有顶点的全排列，随着顶点数的增加，会产生组合爆炸，它是一个NP完全问题。(Traveling Salesman Problem (TSP) is a classic combinatorial optimization problem. The classic TSP can be described as: a merchandiser sells goods to several cities. The salesman starts from a city and needs to go through all the cities and return to the starting point. How to choose the route of travel so that the total journey is the shortest. From the point of view of graph theory, the essence of the problem is to find a Hamilton loop with the smallest weight in a completely undirected graph with weights. Since the feasible solution to this problem is the full permutation of all vertices, as the number of vertices increases, a combinatorial explosion occurs, which is an NP-complete problem.)
- 2020-06-17 11:00:02下载
- 积分：1
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CH11-KEA128-SPI
说明： 1. 硬件接线
（1）调试串口(UART_Debug)使用UART2，在“printf.h”文件中宏定义， 对应引脚为TX-PTD7，RX-PTD6
（在“uart.h文件中宏定义）。
（2）灯0~3（LIGHT_0~LIGHT_3）对应的引脚是PTC0~PTC3，高电平点亮（由硬件接法决定）
（3）SPI0_CLK对应的引脚是PTE0， SPI0_MOSI对应的引脚是PTE1，
SPI0_MISO对应的引脚是PTE2，SPI0_PCS对应的引脚是PTE3，
SPI1_CLK对应的引脚是PTG4， SPI1_MOSI对应的引脚是PTG5，
SPI1_MISO对应的引脚是PTG6，SPI1_PCS对应的引脚是PTG7。
（4）SPI0作为master,SPI1作为slave，SPI1接收SPI0发送的数据并产生中断。
用导线将PTE0与PTG4对接，将PTE1与PTG5对接，将PTE2与PTG6对接，将PTE3与PTG7对接。(1. Hardware wiring
(1) Debugging Serial Port (UART_Debug) uses UART2, macro-defined in "printf.h" file, corresponding pins are TX-PTD7, RX-PTD6.
(macro definition in the uart.h file).
(2) The pins corresponding to the lamp 0~3 (LIGHT_0~LIGHT_3) are PTC0~PTC3, and the high-level lighting is determined by the hardware connection.
(3) The pin corresponding to SPI0_CLK is PTE0, and the pin corresponding to SPI0_MOSI is PTE1.
The pin corresponding to SPI0_MISO is PTE2, and the pin corresponding to SPI0_PCS is PTE3.
The pin corresponding to SPI1_CLK is PTG4, and the pin corresponding to SPI1_MOSI is PTG5.
The pin corresponding to SPI1_MISO is PTG6, and the pin corresponding to SPI1_PCS is PTG7.
(4) SPI0 acts as master and SPI1 acts as slave. SPI1 receives data sent by SPI0 and generates interruption.
PTE0 and PTG4 are docked by wire, PTE1 and PTG5 are docked, PTE2 and PTG6 are docked, PTE3 and PTG7 are docked.)
- 2020-06-16 12:00:01下载
- 积分：1
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可以了吧，这是有关计算物理中用蒙特卡罗方法编程的，好好看吧...
可以了吧，这是有关计算物理中用蒙特卡罗方法编程的，好好看吧-be all right, which is used in the calculation of Physics Monte Carlo method of programming, sees good
- 2023-01-28 20:55:04下载
- 积分：1
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分析计算电网谐波，得出基波和高次谐波的值
单相半波整流电路谐波分析，可以计算谐波的幅值，谐波含量并画图(Single-phase half-wave rectifier circuit harmonic analysis, harmonic amplitude can be calculated, harmonic content and drawing)
- 2017-09-04 16:12:01下载
- 积分：1
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09-MIMO系统容量仿真程序
说明： function C=capacity(SNR,Nt,Nr)
%SNR=0; %定义信噪比为0HZ
A=10^(SNR/10); %信噪比的单位转换关系式
Im=eye(min(Nr,Nt)); %这里的"1"为发射天线和接收天线两者数目少的根数
sum=0; %初始化sum为0
for i=1:10000 %程序循环10000次
H=randn(Nr,Nt); %产生高斯信号源
if Nr<Nt
Q=H*H'; %求威沙特矩阵
else
Q=H'*H;
end
sum=sum+log2(det(Im+A*Q/Nt)); %10000次循环得到的信道容量总和
end
C=sum/10000 %10000次循环的平均值(function C=capacity(SNR,Nt,Nr)
%SNR = 0;% defines SNR as 0Hz
A = 10 ^ (SNR / 10);% s / N unit conversion relation
Im = eye (min (NR, NT));% here "1" is the number of the less number of transmitting antenna and receiving antenna
Sum = 0;% initialize sum to 0
For I = 1:10000% program cycles 10000 times
H = randn (NR, NT);% produces Gaussian signal source
if Nr<Nt
Q = h * H ';% to find the weissard matrix
else
Q=H'*H;
End
Sum = sum + log2 (DET (IM + A * q / NT));% sum of channel capacity from 10000 cycles
End
C = sum / 10000% average of 10000 cycles)
- 2020-09-12 04:39:02下载
- 积分：1
