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使用说明. 一、为什么要进行大气纠正? (1) 太阳辐射通过大气以某种方式入射到物体表面 ... 用户可以选择MODTRAN 模型的光谱分辩率. 三、如何使用F...
使用说明. 一、为什么要进行大气纠正? (1) 太阳辐射通过大气以某种方式入射到物体表面 ... 用户可以选择MODTRAN 模型的光谱分辩率. 三、如何使用FLAASH. 打开FLAASH ...
-modtan
- 2022-01-26 06:55:30下载
- 积分:1
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mt7601u-master
说明: Many usb Wi-Fi adapters that claim to have an RT5370 chipset actually have an MT7601 chipset. There are no drivers in Linux that support this device. This driver can be used to set up a hotspot with these devices. This has compiled and works on the following kernels:
- 2020-09-24 10:06:34下载
- 积分:1
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SAEJ1979-2007中文
说明: J1979 中文,开发OBD检测的可以参考(J1979 Chinese version, you can refer to the development of OBD detection)
- 2020-11-25 12:37:00下载
- 积分:1
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774547
ACM关于图论相关的知识,都是一些模板代码,对参加ACM竞赛非常有用的,()
- 2018-07-07 07:31:43下载
- 积分:1
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Python源码剖析
说明: python源码剖析,带详细目录,觉得好请点赞(Python source code analysis)
- 2020-06-24 00:00:08下载
- 积分:1
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Multisim
可以控制RC电路在半程急速上升和下降,可类比水流等过程的控制。(It can control the rapid rise and fall of water flow in half way.)
- 2020-06-20 04:00:02下载
- 积分:1
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这是一个Prolog实现解决一个迷宫
this a prolog implementation to solve a single maze-this is a prolog implementation to solve a single maze
- 2023-07-05 08:05:03下载
- 积分:1
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悬臂梁MATLAB有限元算例注释
梁可视为平面应力状态,先按图示尺寸划分为均匀的三角形网格,共有8×10=80个单元,5×ll=55个节点,坐标轴以及单元与节点的编号如图。将均布载荷分配到各相应节点上,把有约束的节点5l、52、53、54、55视作固定铰链,建立如图所示的离散化计算模型。(The beam can be regarded as a plane stress state. Firstly, the beam is divided into uniform triangular meshes according to the graphic size. There are 8*10=80 elements, 5*ll=55 nodes. The coordinate axis and the numbering of elements and nodes are shown in the figure. The uniform load is distributed to the corresponding nodes, and the constrained nodes 5l, 52, 53, 54 and 55 are regarded as fixed hinges. The discrete calculation model shown in the figure is established.)
- 2018-12-25 15:34:00下载
- 积分:1
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DynamicDataDisplay-example-master
说明: 一款强大的图表框架,支持大数据图形显示(通过图片方式)(DynamicDataDisplay-example-master)
- 2020-06-17 10:00:02下载
- 积分:1
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FreeRTOS实时内核_实用指南
FreeRTOS实时内核_实用指南 原版本英文的中文翻译版本(FreeRTOS translated to chinese)
- 2020-06-15 22:30:02下载
- 积分:1