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mcclellan
《基于计算机的信号处理实践》
著者： （美）麦克莱伦等著
作译者： 栾晓明译
ISBN号： 7-121-02023-8
出版日期： 2006-01
出版社：电子工业出版社
内含书用使用到的资源：例子所需的MAT文件信号，以及程序用用到的子程序代码。()
- 2020-11-22 20:39:34下载
- 积分：1
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Simulink1
说明： 介绍SIMULINK的电子文档，很实用，内容很详细，对于利用SIMULINK搭建模型仿真的同学很实用(Introduction SIMULINK electronic documents, it is practical, the content is very detailed model for simulation using SIMULINK to build the students very practical)
- 2011-03-14 09:31:52下载
- 积分：1
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mysegment
我自己编写的基于遗传算法的一维最大熵KSW阈值分割代码。(I have written the one-dimensional maximum entropy threshold segmentation based on genetic algorithm KSW code.)
- 2013-07-11 10:43:30下载
- 积分：1
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Sand-pile
一堆沙子的横截面，可以使用 Margolus 型邻居仿真，但运动规则不同。
规则：
元胞有 2 个状态。状态= 0 是空的，状态= 1 代表沙子。
在任何时间步长，一个粒子，可以在2x2 块中向着底部运动。可能运动如下
所示。墙壁和底部将阻止粒子继续运动。
为了让该运动略有随机性，我亦补充说一项规则，有时处于下落状态的两个元胞还旋转，直到所有的动作都完成。(Cross-section of a pile of sand, you can type using the Margolus neighborhood simulation, but the movement rules are different. Rules: There are two cellular states. State = 0 is empty, state = 1 for sand. At any time step, a particle can be in the 2x2 block toward the bottom of the movement. May exercise the following. Walls and bottom to prevent the particles continue to campaign. To make the campaign a little random, I also added a rule, sometimes in the falling state of the two cell also rotate until all actions are completed.)
- 2011-06-30 20:01:06下载
- 积分：1
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NewtonRaphson_0.5
matlab code for Newton-Raphson solver
- 2015-02-03 15:54:26下载
- 积分：1
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lte
SIMULATING THE LONG TERM EVOLUTION PHYSICAL LAYER
- 2014-01-02 23:30:02下载
- 积分：1
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GeneralDigest
base implementation of MD4 family style digest as outlined in "Handbook of Applied Cryptography", pages 344 - 347.
- 2014-02-18 12:17:17下载
- 积分：1
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chap_11
matlab从入门到精通第11章书后源码对初学者很有帮助(matlab)
- 2009-03-19 06:15:41下载
- 积分：1
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matlab_and_examples
介绍MATLAB编程并且还有实例，供大家参考(Introduced and there are examples of MATLAB Programming)
- 2010-03-09 18:36:33下载
- 积分：1
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test_uncoded_BPSK
说明： 未编码传输AWGN信道测试
每帧的输入是相同的，（不是每帧都不一样，这样可以大幅降低计算量）
在帧比特足够多的情况下，应该可以保证随机性(AWGN channel is not coded transmission test input of each frame is the same, (not every frame is different, this can significantly reduce the computation) are enough bits in the frame of the case, should be able to guarantee randomness)
- 2011-03-09 15:56:19下载
- 积分：1
