登录
首页 » LabView » USB摄像头图像采集单帧图像

USB摄像头图像采集单帧图像

于 2020-06-24 发布 文件大小:16KB
0 185
下载积分: 1 下载次数: 1

代码说明:

  利用电脑的摄像头或者外部的USB摄像头,采集图片。(Use a computer camera or an external USB camera to collect pictures.)

文件列表:

USB摄像头图像采集单帧图像.vi, 45325 , 2019-07-16

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • TestWindowsServer
    Windows服务的源码,实现了Windows服务的整个过程,可直接使用(Source Windows services, Windows services to achieve the whole process, and can be used directly)
    2013-11-28 10:01:18下载
    积分:1
  • 起凡全图易语言源码
    起凡全图易语言源码 基址已过期写法提大家学习
    2013-12-03 11:25:02下载
    积分:1
  • 利用vc6.0开发,可以监控网络实时监控网络流量,同时利用图像分析显示网络流量大小。值得参考。
    利用vc6.0开发,可以监控网络实时监控网络流量,同时利用图像分析显示网络流量大小。值得参考。-Vc6.0 use development, the network can monitor real-time monitoring of network traffic, while the use of image analysis showed that the size of network traffic. Worth considering.
    2022-09-19 14:55:03下载
    积分:1
  • wifferent
    说明:  不同的相邻分组数目v实现的pts抑制ofdm峰均比的算法,可以仿真出v越大,papr的性能越好(The algorithm of reducing ofdm peak-to-average ratio by pts with different number of adjacent packets v can be simulated that the larger v is, the better the performance of papr is.)
    2021-05-13 23:30:03下载
    积分:1
  • SCadsAPI
    A documented functions of the synchronous memory chip cards api for gemalto readers that should be used for such cards.
    2011-01-28 19:24:07下载
    积分:1
  • 用户管理_Usermanagement
    采用数据保存用户名、密码等数据,同时具备修改、添加、删除用户信息等(User name, password and other data are saved by data, and user information can be modified, added and deleted at the same time)
    2020-06-18 02:40:02下载
    积分:1
  • 计算器
    这是一个用c#开发的简易计算器,包括加减乘除等功能(This is a simple calculator developed with c#)
    2018-04-01 15:31:39下载
    积分:1
  • 对NDIS开发资料整理,分了6个部分,做了一个完整的目录
    对NDIS开发资料整理,分了6个部分,做了一个完整的目录-NDIS
    2022-09-21 17:10:03下载
    积分:1
  • zoj1094
    zoj094 Matrix multiplication problem is a typical example of dynamical programming. Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose. For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix. There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C). The first one takes 15000 elementary multiplications, but the second one only 3500. Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy. (Matrix multiplication problem is a typical example of dynamical programming. Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose. For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix. There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C). The first one takes 15000 elementary multiplications, but the second one only 3500. Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy. )
    2012-06-10 10:38:53下载
    积分:1
  • pointer-program
    常见的指针编程题目和对应的程序答案,适合C语言初学者使用。(Common pointer programming problem and the corresponding procedures, suitable for beginners to use C language)
    2013-08-29 14:43:13下载
    积分:1
  • 696518资源总数
  • 104269会员总数
  • 31今日下载