登录
首页 » Fortran » DFIG_FRTC_crowbar_2

DFIG_FRTC_crowbar_2

于 2017-11-08 发布 文件大小:24KB
0 116
下载积分: 1 下载次数: 19

代码说明:

  双馈风机模型,可以对参数进行修改,进行仿真(The model of doubly fed induction generator can be modified and simulated)

文件列表:

DFIG_FRTC_crowbar_2.psc

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • OFDMSimulation
    详细介绍OFDM仿真过程,包括信源的产生,信道的加入,编码解码以及LS,MMSE,SVD三种信道估计方法(Detailed OFDM simulation process, including source generation, the addition of channel coding and decoding LS, MMSE, SVD three channel estimation methods)
    2020-07-10 14:38:56下载
    积分:1
  • OpenGL_ES_1.0.2_Sample.zip, based on Qualcomm
    OpenGL_ES_1.0.2_Sample.zip,基于高通BREW平台的的3D游戏引擎.喜欢朋友请下载-OpenGL_ES_1.0.2_Sample.zip, based on Qualcomm
    2023-03-25 15:10:03下载
    积分:1
  • (譜面製作)官方NoteTool
    说明:  O2JAM NOTE TOOLS CHINA
    2019-06-26 17:04:34下载
    积分:1
  • 国内类似ACDsee的一个的查看各种图片的工具源码,含有查看图片缩略图,放大缩小查看,支持bmp,jpg,png,gif等多种格式图片...
    国内类似ACDsee的一个的查看各种图片的工具源码,含有查看图片缩略图,放大缩小查看,支持bmp,jpg,png,gif等多种格式图片-ACDSee domestic similar view of a tool for a variety of picture source containing View picture thumbnails, zoom view, support bmp, jpg, png, gif image formats, etc.
    2023-02-15 06:50:03下载
    积分:1
  • Load1997
    说明:  2001年欧洲智能技术网络组织了一次电力负荷预测竞赛,提供了历史负荷数据、节假日数据和气象数据,对学习负荷预测有帮助(In 2001, the European intelligent technology network organized a power load forecasting competition, providing historical load data, holiday data and meteorological data, which is helpful for learning load forecasting)
    2019-12-30 15:41:40下载
    积分:1
  • 01-2_crankshaft_asm
    说明:  12345679987461232adafsafadffssagdah
    2020-06-23 09:40:02下载
    积分:1
  • IST算法
    说明:  在IST函数中,一共规定了三种IST跳出迭代的条件:第一个是重构结果经Phi变换后与原先y的差异,第二是最大迭代次数,第三个是重构结果x两次相邻迭代的差异(In ist function, there are three kinds of conditions for ist to jump out of iteration: the first is the difference between the reconstruction result after Phi transformation and the original y, the second is the maximum number of iterations, and the third is the difference between two adjacent iterations of reconstruction result)
    2020-12-12 19:38:06下载
    积分:1
  • Roman numerals simple conversion process, c++ to achieve
    简单的罗马数字转换程序,将罗马数字转换成阿拉伯数字,c++实现-Roman numerals simple conversion process, c++ to achieve
    2022-04-21 10:41:49下载
    积分:1
  • Assignment Questions BEEE Unit 4
    说明:  basic electrical assignment questions
    2019-04-02 17:02:46下载
    积分:1
  • Laborator 8 - Scripturi shell
    linuxshel scripts tutorial ro
    2020-06-25 20:00:02下载
    积分:1
  • 696518资源总数
  • 104384会员总数
  • 26今日下载