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347013
说明： OPNET 无线仿真 PPT + 源码 好好学习吧(OPNET wireless simulation PPT source code)
- 2019-01-04 05:14:51下载
- 积分：1
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control2
这是一个在控制面板中增加自己软件所需配置属性的源程序。(This is an increase in the control panel software required for their configuration properties of the source.)
- 2013-07-01 20:28:56下载
- 积分：1
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Camera_EXG50_GigE
Initialise and acquisition of Camera EXG50 GigE
- 2011-12-20 17:32:53下载
- 积分：1
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DirecteryOption
模拟终端，和几种目录文件操作的系统命令，dir,cd,md,del等(analog terminal, and several catalog operation of the system commands, dir, cd, md, del etc.)
- 2005-05-10 21:37:39下载
- 积分：1
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medo
设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组，每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。 编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n（n<=200），表示每个数组有n个数。接下来的两行分别是X，Y数组的元素。结果输出 程序运行结束时，将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits. programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)
- 2021-03-22 16:29:16下载
- 积分：1
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Queue
队列的顺序定义，队列的调用算法等，队列的模板类及其实现(Defined in the order queue, queue calls algorithm, queue template class and its implementation)
- 2013-07-17 15:42:54下载
- 积分：1
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versinfo
class for retrival of executable file and product version information from VERSIONINFO resource in C++
- 2012-10-19 00:30:05下载
- 积分：1
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travelingsalesman
用动态规划法求解旅行商问题 已经加入注释 欢迎批评指正(dynamic programming method for the traveling salesman problem has joined Notes welcome criticism correction)
- 2005-06-09 15:40:17下载
- 积分：1
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674569
PPC开发的代码, 希望我们大家共同努力共同分享,请大家多多指教,互相帮助(PPC development code, I hope we all work together to share, please advise and help each othe)
- 2019-01-04 05:55:53下载
- 积分：1
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template
template 模版函数 函数模版 深入了解(template template template-depth understanding of the function function)
- 2013-07-15 17:33:53下载
- 积分：1
