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get_point_v1
segment and clustring
- 2010-12-26 01:13:59下载
- 积分：1
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20065523575588940
这是篇关于左手材料的PPT，比较简单，适合于刚入门的人(This the chapter on the left hand material PPT, relatively simple and suitable for people who just look at the portal)
- 2007-05-21 18:16:15下载
- 积分：1
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AR
说明： 基于AR模型，通过已有的70个随机数进行的预测。用matlab实现。(AR-based model, the random number 70 has been carried out predictions. Using matlab implementation.)
- 2011-03-28 16:38:29下载
- 积分：1
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cv
说明： vectoriel control of synchronious machines
- 2010-05-22 00:15:46下载
- 积分：1
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musiic_like
采用四阶累积量的对DoA进行估计，主要采用Music-like的方法(Fourth-order cumulant on the DoA estimates, the main Music-like)
- 2020-09-01 15:08:10下载
- 积分：1
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MFIE
MFIE.m
本程序用于磁场积分方程求解圆柱散射
- 2010-05-14 10:53:12下载
- 积分：1
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lyapunov
lyapunov指数总结,讲的很详细，是学习的好资料，大家快下载吧(Lyapunov index, speak very detailed, is learning good information, everyone to download)
- 2013-09-02 19:00:26下载
- 积分：1
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ICA-overview
独立分量分析的概述，有利于初步的接触独立分量分析，(Overview of independent component analysis, which is beneficial to the initial contact independent component analysis,
)
- 2011-12-15 20:26:19下载
- 积分：1
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QAM
编写一个含QAM传输的发送和接收模块
1)分别采用复基带仿真和实带通仿真两种形式
a) 实带通仿真时, 载波频率为符号率的4倍
b)发端采用滚降系数0.5的根号升余弦滤波器
2)画出Eb/N0=15dB时的接收波形(收滤波前),取100个采样
3)画出发端输出的眼图和收端过匹配滤波后的眼图(画眼图时不加噪声)
统计误符号率和误比特率与Eb/N0的关系,画出曲线, 与理论计算的曲线相对比
(Prepare to send of one with QAM transmission and receiver module 1), respectively, the complex baseband simulation and the real band-pass simulation in two forms a) the real band-pass simulation, the carrier frequency used for the symbol rate of 4 times b) the originator roll-off factor of 0.5 root raised cosine filter, 2) draw Eb/N0 = 15dB when the received waveform (closing filter), take 100 samples) to draw the originator of the output eye diagram and income side of the eye diagram after the matched filter ( draw the eye diagram without noise) statistics symbol error rate and bit error rate and Eb/N0, draw a curve calculated with the theoretical curve compared)
- 2012-05-29 16:51:47下载
- 积分：1
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QRDCMP
用镜像矩阵求出矩阵的QR分解（正交三角分解），并求解线性方程组，该方法不必选主元，但其计算过程非常稳定。也可用于求矩阵的广义逆和求解线性最小二乘问题。子过程QRDCMP用镜像矩阵求m*n矩阵A的QR分解，A=Q^TR,其中Q是m*m正交矩阵，R为m*n上三角矩阵；子过程QRBKSB用矩阵的QR分解求解线性方程组Ax=b，其中A为n阶非奇异方阵。(Matrix obtained with the mirror matrix QR decomposition (orthogonal triangular decomposition), and solving linear equations, the method does not have to choose the main element, but its calculation process is very stable. Can also be used to find the generalized inverse matrix and solving linear least squares problems. Sub-process of the mirror matrix QRDCMP m* n matrix A QR decomposition, A = Q ^ TR, wherein Q is a m* m orthogonal matrix, R is m* n upper triangular matrix subprocess QRBKSB a QR decomposition to solve the matrix linear equations Ax = b, where A is non-singular square matrix of order n.)
- 2013-09-27 11:05:18下载
- 积分：1
