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21840286GML_AdaBoost_Matlab_Toolbox_0[1].3
AdaBoost实现算法（外国人写的，有详细的分析）(AdaBoost algorithm (written by foreigners, a detailed analysis))
- 2020-07-17 14:28:50下载
- 积分：1
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Orbit
卫星轨道机动模拟仿真matlab程序，应用GPS数据进行具体分析。(Matlab simulation of satellite orbit maneuver, application specific analysis of GPS data.)
- 2010-02-03 10:34:51下载
- 积分：1
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Rrs--matlaabS
RS码的matlabb仿真非常有帮助的东西，完整源代码。
(RS code matlabb simulation is very helpful things, complete source code.)
- 2012-07-10 09:05:38下载
- 积分：1
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elman_matlab
实现elman神经网络进行故障分析，对电机进行故障判别和分析(elman ANN analysing faults of electric machinery)
- 2014-05-22 17:04:44下载
- 积分：1
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33333RLS
RLS算法，用matlab实现，用最小二乘法来实现均衡，程序正确(RLS algorithm, using matlab to achieve, using the least squares method to achieve a balanced and correct procedures)
- 2012-09-05 21:49:34下载
- 积分：1
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Kalman
kalman跟踪经典实例程序，C语言编写，跟踪鼠标移动(kalman tracking classic example program, C language, tracking mouse movements)
- 2014-12-03 22:12:17下载
- 积分：1
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emd
经验模态分解程序，把信号分解为固有模态函数(the program of emd)
- 2009-10-08 09:44:15下载
- 积分：1
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5
一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。
C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。
系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)
- 2009-03-15 15:36:23下载
- 积分：1
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Alamouti
mimi_ofdm multipath channel emulation, including waveform shape,
- 2009-03-29 10:30:57下载
- 积分：1
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work
Inverted pendulum using fuzzy
- 2010-02-06 13:09:06下载
- 积分：1
