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zhan
队列的顺序存储结构和操作实现
队列的顺序存储结构和操作实现(The order of the queue storage structure and operation of the order of the realization of the queue storage structure and operation of the realization of)
- 2008-12-11 20:10:49下载
- 积分：1
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Brute-force-algorithm
穷举算法，VC中的经典程序之一，适合初学者，(Brute-force algorithm, the the of the classic procedures in in the the VC, suitable for beginners)
- 2012-06-06 21:20:06下载
- 积分：1
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xiererfenchazhao
希尔排序c++数据结构算法
二分查找的递归算法(希尔排序c++数据结构算法
二分查找的递归算法
)
- 2010-12-10 18:32:52下载
- 积分：1
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BeiDa_ACM1702
北大ACM1702题 转换为3进制
很经典(NULL)
- 2009-12-08 11:31:40下载
- 积分：1
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Task1-trial--10211281--zly
描述：足球俱乐部包括球员、普通行政人员。球员有姓名、年龄、能力、年薪、转会费、进球总数、服役年限等重要参数；普通行政人员有姓名、年龄、能力、年薪等参数。你需要给相关管理机构开发一个管理程序，实现对众多足球俱乐部管理的基本功能。具体功能包括：
a) 俱乐部的增删改查，俱乐部的属性包括名称、现金、其下人员；
b) 可以对所有球员的各项属性进行简单搜索，支持输入多个条件，条件之间用&&连接，例如：
i. “年龄不大于25且服役年限大于5年且进球数大于100的球员”，查询表达式：!(@age>25) && @experience>5 && @kick>100
c) 支持球员在不同俱乐部间的买卖，买卖需符合以下条件：作为买方的俱乐部的现金>=球员的转会费，交易完成后，卖方将得到转会费。
要求：
d) 必须采用面向对象的方式，使用类组织数据结构，并注意类的继承关系；
e) 在题目要求基础上可以自行扩展功能，提供扩实用扩展功能者适当加分（加分不超过5分）。
(Description: Football club including players, general administrative staff. Player name, age, ability, salary, transfer fee, total number of goals, service life and other important parameters ordinary administrative staff name, age, ability, salary and other parameters. You need to give the relevant management agencies to develop a management program to achieve the number of football club management s basic functions. Specific features include:
a) the club CRUD, the name of the club s property, including cash, under which personnel
b) all players can perform a simple search of the property, supports input multiple conditions with && connection between conditions, for example:
i. "Age is not greater than 25 and greater than 5 years service life and goals more than 100 players," query expression:! (@ age> 25) && @ experience> 5 && @ kick> 100
c) Support the players traded between different clubs, the sale subject to the following conditions: As a buyer s club cash> = pl)
- 2013-08-20 10:09:29下载
- 积分：1
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chess
在N*N的棋盘上(1<=N<=10)填入1,2,...N*N共N*N个数,使得任意两个相邻的数之和为素数. (In the N* N chessboard (1 < = N < = 10) filled 1,2, ... N* N total number of N* N so that any two adjacent numbers and prime numbers.)
- 2009-06-01 11:21:39下载
- 积分：1
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migong
简单的迷宫问题，有点土，还望大家多指点指点，在此感激不尽。(????? mad spasm, ? Tang Gao, ? oligonucleotide ??? Ning Ning ? ?, Hitomi ?????.)
- 2008-07-05 00:11:37下载
- 积分：1
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BDX
设计、编写和调试面向对象C++程序，实现任意两个同类数据比大小
的通用函数（模板），涵盖普通数值型数据之间的比较、两个字符串之间的比较
（按字典序）、两个复数之间的比较（按模大小）等，并通过主函数加以调用和
测试。(Design, writing and debugging of object-oriented C++ procedures to achieve similar data than the size of any two generic functions (template), covering general comparison between numerical data, the comparison between the two strings (lexicographically), two Comparison between complex numbers (modulo the size), and through the main function to be invoked and tested.)
- 2020-11-28 13:49:29下载
- 积分：1
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polynomial
说明： 线性表的基本运算及多项式的算术运算在顺序表泪SeqList 中增加成员函数void Reverse()实现顺序表的逆置
(Linear form the basic arithmetic operations and the polynomial form in order to increase tear SeqList member function void Reverse () to achieve the inverse order of the table set)
- 2010-04-20 20:11:40下载
- 积分：1
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Devillanguage1
Devil language
数据结构中的经典问题
此为问题!(Devil language data structure of the classic problems of this problem!)
- 2006-10-17 23:42:17下载
- 积分：1
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