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Basic-Interface
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//
// ImageAndTextCell.h
// SimpleTreeController
//
// Created by System Administrator on 7/13/11.
// Copyright 2011 __MyCompanyName__. All rights reserved.
//
- 2014-01-21 17:47:36下载
- 积分：1
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Array-type-high-precision-degree
详细介绍了数组高精度数，通过这个资料可以很好的学习如何使用(Introduces in detail to solve the array degree, through this material can be very good learning how to use
)
- 2012-11-04 11:06:32下载
- 积分：1
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StarRat
START RAT远控源码START RAT远控源码START RAT远控源码START RAT(START START RAT RAT far point source code remote control the source code START START RAT RAT far point source code)
- 2014-02-25 09:10:34下载
- 积分：1
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particle
说明： OSG例子系统 用一个飞机起火的模型说明例子系统的生成和实现(OSG example of the system model with a plane on fire examples of systems that generate and implement)
- 2011-04-03 21:38:08下载
- 积分：1
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5
一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。
C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。
系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)
- 2009-03-15 15:36:23下载
- 积分：1
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skills_for-VC-MATLAB_combined_coding
VC与matlab接口编程,matlab 强大的数学分析能力，结合VC强大的编程，那么接口程序如何编写就显得重要了。(VC interface with matlab programming, matlab powerful mathematical analysis capabilities, combined with powerful programming VC, then the interface program on how to prepare it is important.)
- 2009-06-06 23:08:38下载
- 积分：1
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adpcm
g.722 code for speech compression
- 2010-03-02 16:08:59下载
- 积分：1
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newton
用牛顿迭代法求方程
f(x)=x³ -x² -1=0
在x。=1.5附近的一个实根。取§=0.000001，取最大迭代数为60.
(With Newton iteration equation for f (x) = x ³-x ² -1 = 0 in x. = 1.5 near the root of a real. Take § = 0.000001, take the largest number of 60 iterations.)
- 2009-06-20 22:57:57下载
- 积分：1
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mapwindow6-81799
mapwindow6的源码。对于学习提高非常有用(mapwindow6 source. Very useful for learning to improve.)
- 2013-11-17 09:46:02下载
- 积分：1
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109201293CSharp_MATLAB
interop between C# and matlab
- 2009-05-17 13:21:18下载
- 积分：1
