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Global-Newton-Raphson
全局牛顿-拉普森方法求解非线性方程组，自动搜索步长，进一步保证了程序的收敛(Global Newton-Raphson method for solving nonlinear equations. The steps can be found automatically. The convergence is better than the common Newton-raphson method.)
- 2013-06-27 12:00:34下载
- 积分：1
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forward-finite-difference-method-
地震勘探中，有限差分正演方法的简单一维数值模拟(Seismic exploration, forward finite difference method is simple one-dimensional numerical simulation)
- 2021-04-07 20:59:01下载
- 积分：1
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Stanford
说明： 并联机器人standFord，其数值解及解析解，正解和逆解以及雅可比矩阵及动力学问题分析(Standford series robot, its numerical solution and analytical solution, positive solution and inverse solution, Jacobian matrix and dynamics analysis)
- 2021-01-21 16:41:14下载
- 积分：1
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混合同余法
说明： 用混合同余法生成两组伪随机数，利用投针试验求圆周率。软件：matlab。(Two groups of pseudo-random numbers are generated by the method of mixed congruence, and the circularity is calculated by the test of inserting needle. Software: MATLAB.)
- 2020-04-06 10:23:11下载
- 积分：1
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sun_azimuth_data
根据经度纬度时间，计算太阳的方向角，matlab源码，附有详细的文档注释。(According to longitude latitude time, calculating the direction of the sun angle, matlab source, with detailed documentation of the Notes.)
- 2008-03-06 20:00:24下载
- 积分：1
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LU-SGS
利用时域有限差分求解CFD问题，其中差分格式为LUSGS，是求解流体问题的理论基础(Solved using finite-difference time-domain CFD problems, in which the differential form LUSGS
)
- 2011-12-15 22:43:30下载
- 积分：1
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shiyan4
若矩阵A中的某一元素A[i，j]是第i行中的最小值，而又是第j列中的最大值，则称A[i，j]为矩阵A中的一个鞍点。请写出一个可确定此鞍点位置的算法（如果这个鞍点存在）。(If the matrix A, an element A [i, j] is the minimum value in the i-th row, but is the maximum value of the j-th column, then A [i, j] for the matrix A is a saddle point. Please write a algorithm to determine the position of saddle point (saddle point exists).)
- 2013-01-07 13:16:11下载
- 积分：1
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FEM-of-four-bar-truss-structures
四杆桁架结构的有限元分析程序，在VS2008软件中使用C++语言编写，输入为四杆桁架结构的节点坐标，材料参数，边界条件，输出为各节点的应力和应变。(Four-bar truss structure finite element analysis program, the use of C++ written in VS2008 software, input node coordinate the four-bar truss structure, material parameters, boundary conditions, the output of the stress and strain of each node.)
- 2015-06-22 10:03:42下载
- 积分：1
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FFT
提供函数能进行1维2维的FFT，输入输出的序列长度应为2的整数次方倍(Provides functions can be one-dimensional two-dimensional FFT, sequence length input and output should be an integer power of 2 times)
- 2014-01-07 22:10:34下载
- 积分：1
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RSM
响应面方法的一个例子，二阶响应面，使用正交矩阵法求解(rsm algorithms )
- 2009-11-10 22:32:19下载
- 积分：1
