登录
首页 » matlab » rengongshichang

rengongshichang

于 2014-12-30 发布 文件大小:5KB
0 116
下载积分: 1 下载次数: 114

代码说明:

  改进人工势场避障程序,用于移动机器人轨迹规划(Improved artificial potential field obstacle avoidance program for mobile robot path planning)

文件列表:

rengongshichang
...............\compute_angle.m,574,2014-12-30
...............\compute_Attract.m,307,2014-12-30
...............\compute_repulsion.m,1538,2014-12-30
...............\rengongshichang.m,2632,2014-12-30
...............\xiugai.m,5121,2014-12-30

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • Newton
    用matlab编写的实现牛顿插值法的代码,生成图像可显示节点数,误差点。(Prepared with the matlab code to achieve Newton interpolation to generate the image to show the number of nodes, the error point.)
    2010-12-27 18:21:04下载
    积分:1
  • timesyn
    说明:  通信系统中的定时同步仿真,经过matlab调试和编译,可实现定时信息提取和误差估计检测!!(Timing synchronization in communication systems simulation, debug and compile through matlab, timing information can be extracted to achieve detection and error estimates! !)
    2010-04-21 11:03:14下载
    积分:1
  • simbubble
    simulation of ultrasonic cavitation. to use with RP function file in order to plot bubble radius time development.
    2011-08-25 23:34:50下载
    积分:1
  • Encription_Decription_Code
    Matlab Code for Watermarking. This code is useful for elliptic curve cryptography
    2014-11-29 19:06:41下载
    积分:1
  • ASK
    Script in Matlab, Modulation ASK
    2011-07-02 08:10:47下载
    积分:1
  • Statisticalparameterscalculatedimage
    有四个单独的MATLAB程序,是对一幅256的单色图像进行最大值计算,最小值计算,均值计算,还有一个是画出其直方图(four separate MATLAB program is to a 256 monochrome image maximum, minimum, mean, there is a painted its histogram)
    2007-05-20 21:41:20下载
    积分:1
  • shezhen
    掌握舌象裂纹分析技术,能够根据舌象的纹理粗糙与细腻区别老嫩舌。(Grasp the tongue as crack analysis technology, according to the texture of the tongue as rough and delicate difference between the old tender tongue.)
    2020-08-14 10:08:26下载
    积分:1
  • MATLAB_Wavelet_analysis
    张德丰《MATLAB 小波分析》光盘源代码(Zhang Defeng " MATLAB wavelet analysis," the source code CD-ROM)
    2010-07-08 22:43:24下载
    积分:1
  • ForK1
    我们的目的是将一个分数拆分成若干个分子是1分母是正整数的分数之和的形式。例如2/3可以拆分成1/2+1/6的形式。这里不考虑顺序,比如1/6+1/2和1/2+1/6相同。 输入p, q, a, n, 其中p/q为分数,对这个分数进行拆分,要求拆分的分数个数不能多于n个,所有分母的乘积不能大于a。求有多少种拆分方法? 输入:最多200组数据。在每行中都有四个数分别表示p, q, a, n,之间以空格隔开,并且满足p,q<=800,a<=12000,n<=7,最后以四个0做为输入的结束。 输入示例: 2 3 120 3 2 3 300 3 0 0 0 0 输出示例: 4 7 (Our aim is to split a fraction into a number of elements is a denominator is a positive integer fraction of the sum of form. For example, 2/3 can be split into 1/2+1/6 form. Not considered here, the order, such as 1/6+1/2 and 1/2+1/6 of the same. Input p, q, a, n, where p/q as a fraction of this split scores require no more than the number of split points n-all the product of the denominator can not be larger than a. How many kinds of demand split method? Input: Up to 200 sets of data. In each line has four numbers indicate the p, q, a, n, separated by a space between, and meet the p, q < = 800, a < = 12000, n < = 7, the end, four 0 as the input end. Input Example: 2,312,032,330,030,000 sample output: 47)
    2009-11-12 09:54:17下载
    积分:1
  • mat
    matlab programs miscellaneous
    2012-05-29 02:50:00下载
    积分:1
  • 696518资源总数
  • 104269会员总数
  • 42今日下载