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m
题目：有1、2、3、4个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？
1.程序分析：可填在百位、十位、个位的数字都是1、2、3、4。组成所有的排列后再去
掉不满足条件的排列。
(Title: There are numbers 1,2,3,4, how many can be composed of distinct three-digit numbers without repetition? Is how much? 1. Program Analysis: fill in the hundred, ten, a bit of the numbers are 1,2,3,4. Composed of all the permutations and then remove the arrangement does not meet the conditions.)
- 2011-05-23 17:49:15下载
- 积分：1
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FaceRecog
Face regno for tools detection face. and than regno sample face to be compare in database face
- 2012-05-07 01:34:31下载
- 积分：1
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tutor
The project manager in MPLAB v3.40 has been extended to support multiple files. Previously established
projects from MPLAB v3.31 and earlier will be converted automatically by MPLAB v3.40 when they are
opened. Converted projects cannot be re-opened from previous versions of MPLAB.
- 2011-06-20 03:45:50下载
- 积分：1
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matlab2tikz-matlab2tikz-0.6.0-60-g722609f
matlab code for matlab2tikzmatlab2tikz
- 2015-02-03 15:45:07下载
- 积分：1
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YTY_GA_Final
To find the largest fitness value and its location
寻找最大适应性及相应的位置！ Population N=50；crossover bits=n/2 (half of bits of an individual) with random locations，mutation bits = 4 种群数 N=50，交换位数= n/2, 即个体位数的一半，且位置随机；
变异位数统一取为4；
Nc=20，28，36，44，individuals for crossover(交换的个数)。 Nm=1，5，10，15， individuals for mutation(变异的个数)。 (To find the largest fitness value and its location to find the location of the maximum adaptability and the corresponding! Population N = 50 crossover bits = n/2 (half of bits of an individual) with random locations, mutation bits = 4 population size N = 50, exchange digits = n/2, ie half of the median individual, and random position variation is taken as unity median 4 Nc = 20,28,36,44, individuals for crossover (exchange number). Nm = 1,5,10,15, individuals for mutation (the number of variations.))
- 2010-12-27 21:23:27下载
- 积分：1
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pso
适用的方便实用，运算简单，仅供大家参考，谢谢大家。(Practicability Convenient and practical)
- 2013-01-07 10:35:49下载
- 积分：1
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pinjunshengqiangqifangweigujipinyu
说明： 利用平均声强器法测定目标方位，经验证，估计方位与假设方位一致(The average sound intensity using target orientation determination device, proven, estimates and assumptions bearing the same direction)
- 2010-04-15 11:28:32下载
- 积分：1
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AD
说明： 基于tms5402的 AD转换程序 有项目工程和源程序(Tms5402 based on the AD conversion process and project source code)
- 2009-06-08 20:13:23下载
- 积分：1
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1
说明： matlab实现：
①用乘同余数法产生白噪声 ②遗忘因子递推最小二乘参数估计（FFRLS）③M序列及逆M序列的产生④批处理最小二乘参数估计（LS）⑤产生m序列(Use by remnant produce white noise with law
)
- 2011-12-05 19:03:23下载
- 积分：1
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ca-and-Matlab
CA方法在MATLAB中的实现，介绍了一些基本的元胞自动机方法，并给出了源程序。(The CA method implemented in MATLAB basic cellular automata method, and given the source code.)
- 2013-03-13 16:07:00下载
- 积分：1
