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串口6
说明： 实现串口 高速数据采集并通过波形显示。还有发送按键发送数据给下位机。(High speed data acquisition through serial port is realized and displayed by waveform.)
- 2020-06-03 17:43:29下载
- 积分：1
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带通滤波
说明： 实现带通滤波，在LABVIEW中实现带通滤波。可以运行，大家可以下载看看(Band pass filtering is realized in LabVIEW. It can be run. You can download it)
- 2020-05-12 20:25:14下载
- 积分：1
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labviewmoto
用labview编写的电机控制上位机软件,可以显示电机的当前速度和转速波形图,通过串口通讯(Prepared using LabVIEW motor control PC software, can display the motor speed and speed of the current waveform through the serial communication)
- 2008-03-09 14:05:05下载
- 积分：1
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Tone Measurement
Determine the tone of a given signal.
- 2017-12-14 03:10:16下载
- 积分：1
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The-sound-tech-based-on-Labview
基于Labview的声音检测技术CAA文献，可鉴别人声，运用了Matlab小波分析。(Labview-based voice detection technology CAA literature, can identify the human voice, the use of Matlab wavelet analysis.)
- 2014-05-10 09:39:39下载
- 积分：1
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SQLite API
说明： labview连接sqlite数据库，并能够对数据库操作(LabVIEW connects SQLite database and can operate on Database)
- 2021-03-06 14:39:30下载
- 积分：1
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labview读取USB数据的升级版
USB设备数据读取，将USB中数据保存到电脑上(USB device data read, save the data from USB to the computer)
- 2020-10-16 22:47:28下载
- 积分：1
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labwindows连续数据采集
labwindows连续数据采集，有很强的实用性(labwindows continuous data acquisition)
- 2011-06-13 14:26:54下载
- 积分：1
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LabVIEW_Guide
Labview的详细开发指南，包括：双精度数据不适于相等比较（内置函数）；顺序结构是“结构”吗？；到底什么是“节点”；XY GRAPH的输入参数形式 ；整型数据类型和内存映射；状态机的基本概念 ；状态机的基本类型顺序结构 ；状态机的基本类型之标准状态机 ；事件结构中的TIMEOUT进行数据采集合适吗 ；全局变量、移位寄存器和功能型全局变量的性能比较等。(Labview detailed development guidelines, including: double precision data is not suitable for equality comparison (built-in function) sequential structure is " structural" it? In the end what is " node" input parameters of the form XY GRAPH integer data types and memory mapping basic concept of the state machine basic types of sequential structure of the state machine basic types of state machine standard state machine event structure The TIMEOUT data collection suitable for you global variables, shift registers and functional performance comparison of global variables and so on.)
- 2014-02-07 14:23:43下载
- 积分：1
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求解平方和最大值
说明： 计算1——n的平方和大于1000的n的最小值，并计算出累加和(Calculate the sum of squares of 1-N and the minimum value of N greater than 1000, and calculate the sum of accumulations.)
- 2020-06-18 23:00:02下载
- 积分：1
