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fuzzy
简单介绍了模糊控制器的隶属度函数的matlab代码输入(A brief introduction to the fuzzy controller matlab code input membership function)
- 2013-12-06 21:04:47下载
- 积分：1
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SmartAntenna
这个计划的目的是模拟一个基站接收器（上行的智能天线系统）(This Program is Designed To Simulate The Smart Antenna System On A BTS Receiver ( Uplink )
)
- 2009-11-25 10:16:09下载
- 积分：1
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cartprod
calculates cartesian products of sets
- 2010-12-09 16:04:11下载
- 积分：1
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xaisezengqiangRetinex
说明： 对彩色图像颜色的拉伸，增强图像的对比度，以便更好的研究图像(Stretch of the color image color to enhance image contrast in order to better study the image)
- 2011-03-13 11:13:31下载
- 积分：1
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c3
说明： Electrical machine modelling run the mfile first and run the model file
- 2012-08-02 11:31:02下载
- 积分：1
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kill-hdd
This example shows the complete Kill, Hard Disk
- 2014-01-20 16:31:43下载
- 积分：1
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src-fusion
A. Fusion at the Feature Extraction Level
The data obtained from each sensor is used to compute a
feature vector. As the features extracted from one biometric
trait are independent of those extracted from the other, it is
reasonable to concatenate the two vectors into a single new
vector. The primary benefit of feature level fusion is the
detection of correlated feature values generated by different
feature extraction algorithms and, in the process, identifying a salient set of features that can improve recognition accuracy
[14]. The new vector has a higher dimension and represents the
identity of the person in a different hyperspace. Eliciting this
feature set typically requires the use of dimensionality
reduction/selection methods and, therefore, feature level fusion
assumes the availability of a large number of training data.
- 2013-03-14 16:40:42下载
- 积分：1
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基于微粒群模型的无线传感器网络节点部署研究
基于微粒群模型的无线传感器网络节点部署研究(Research on the deployment of wireless sensor network node based on particle swarm optimization model)
- 2020-07-06 15:58:58下载
- 积分：1
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we
说明： 七单元天线阵DOA估计
clear clc
d=1 天线阵元的间距
lma=2 信号中心波长
q1=1*pi/4 q2=1*pi/3 q3=1*pi/6 q4=3*pi/4 四输入信号的方向
A1=[exp(-2*pi*j*d*[0:6]*cos(q1)/lma)] 求阵因子
A2=[exp(-2*pi*j*d*[0:6]*cos(q2)/lma)]
A3=[exp(-2*pi*j*d*[0:6]*cos(q3)/lma)]
A4=[exp(-2*pi*j*d*[0:6]*cos(q4)/lma)]
A=[A1,A2,A3,A4] 得出A矩阵
n=1:1900
v1=.015 四信号的频率
v2=.05
v3=.02
v4=.035
d=[1.3*cos(v1*n) 1*sin(v2(we)
- 2010-05-06 15:26:50下载
- 积分：1
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iobit_toolbox
help for matlab
- 2011-06-02 08:39:14下载
- 积分：1
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