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G.格子Boltzmann方法的原理及应用
说明： 本书详细介绍了格子波尔兹曼法的原理，边界条件，具体模型及数值方法，非常适合学习与应用。(This book introduce the theory of lattice boltzmann methods alone with it's boundary conditions,models and numerical methods. It's really a book for us to learn and use.)
- 2017-06-22 11:48:09下载
- 积分：1
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[emuch.net][1658947]Console6
计算材料学中用相场法模拟合金凝固相变的程序(Computational Materials Science using phase-field simulation of solidification phase change process)
- 2021-01-28 16:38:34下载
- 积分：1
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istft
说明： 短时傅里叶变换及短时傅里叶反变换的实现，简单可用(The realization of short-time Fourier transform and short-time Fourier inverse transform is simple and available)
- 2019-12-03 20:30:24下载
- 积分：1
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1
说明： 基于高斯赛德尔法的线性方程组解法（可消去系数矩阵病态）。基于牛顿法及改进的牛顿法实现对
非线性方程的求解。(Based Linear Equations high Sisaideer law (coefficient matrix can be eliminated morbid). Realization of nonlinear equations of Newton' s method for solving and improved Newton method is based.)
- 2016-06-30 16:47:29下载
- 积分：1
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BandPass_Filter_Response
用來計算帶通濾波器相關參數，可以看出響應圖(Band-pass filter is used to calculate the relevant parameters can be seen in Fig response)
- 2015-12-14 13:01:47下载
- 积分：1
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migration(FKaPS)
F-K域偏移法和相移法偏移程序（C语言）(FK domain migration method and the phase- shift method migration program (C language))
- 2021-04-06 20:59:02下载
- 积分：1
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sod-problem-by-MacCormack
一维 问题，即激波管问题，是一个典型的一维可压缩无黏气体动力学问题，并有 解析解。对它采用二阶精度 两步差分格式进行数值求解。(Use MacCormack difference scheme for solving a two-dimensional shock tube problem)
- 2014-01-03 09:15:51下载
- 积分：1
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GM(11)
gm模型 gm模型 gm模型 gm模型 gm模型 GM(1,1)(gm model gm model gm model gm model gm model GM (1,1))
- 2006-05-28 09:24:05下载
- 积分：1
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ntontrust5duowei08
解无约束优化问题的锥模型拟牛顿信赖域算法。不同与传统的二次模型方法。(A quasi-Newton algorithm based
on the simple dogleg method is developed.)
- 2009-03-16 14:58:02下载
- 积分：1
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kalman
卡尔曼滤波的源程序，卡尔曼滤波是以最小均方误差为估计的最佳准则，来寻求一套递推估计的算法。它适合于实时处理和计算机运算。
(Kalman filtering of source code, Kalman filter based on minimum mean square error for estimating the best criteria to search for a recursive estimation algorithm. It is suitable for real-time processing and computing.)
- 2008-05-20 22:16:52下载
- 积分：1
