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1-aplikasi-penjualan
Yeah I actually fixed it by moving a bunch of stuff to onResume(). There are also a number of other bugs I found in this code posted here (which was based on even buggier code) that I will post as soon as I get them all fixed. The first one that comes to mind is that in the try block it needs to check if c is null. Another one is that there is no error handling for a source going down midstream
- 2015-03-27 00:50:12下载
- 积分：1
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juanjihe
西安交通大学版信号与系统第一次作业，求数学卷积和C++代码(For convolution and c++ code
)
- 2012-11-07 12:25:28下载
- 积分：1
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D3DXMatrixRotationAxis_analysis
D3DXMatrixRotationAxis 数学原理解析
Axis To Axis 的矩阵生成
介绍广告版的复杂搭建 原理
附录 Matlab 和 C++ 代码
(D3DXMatrixRotationAxis mathematical theory of matrix analysis Axis To Axis generate complex structures introduced principles of billboards Appendix Matlab and C++ code)
- 2010-05-23 15:38:38下载
- 积分：1
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OFDM
OFDM仿真资料，以及一些仿真的程序源代码OFDM仿真资料，以及一些仿真的程序源代码OFDM仿真资料，以及一些仿真的程序源代码(OFDM simulation data, as well as some simulation program source code for OFDM simulation data, as well as some simulation program source code for OFDM simulation data, as well as some simulation program source code for)
- 2009-09-10 15:50:35下载
- 积分：1
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LEACH.m
LEACH的源代码，详细注释，适合初学WSN路由协议的同学学习。(LEACH source code, detailed notes, WSN routing protocols suitable for novice students to learn.)
- 2014-01-17 21:23:03下载
- 积分：1
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ExampleInet
Important skill to learn for Inet tools
full source code
- 2014-10-27 07:14:42下载
- 积分：1
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Laba_0
#include "comparer.h"
#include <iostream>
using namespace std
int Comparer::compareByName(Student& s1,Student& s2)
{
return strcmp(s1.m_szName,s2.m_szName)
}
int Comparer::compareBySurname(Student& s1,Student& s2)
{
return strcmp(s1.m_szSurname,s2.m_szSurname)
}
int Comparer::compareByGroup(Student& s1,Student& s2)
{
- 2010-01-21 00:05:09下载
- 积分：1
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RRG-MAENS
解决大规模限量弧路由的程序，本程序采用了PAM聚类的方法。(To solve large-scale limited arc routing procedures, the program uses a PAM clustering method.)
- 2013-12-03 15:39:31下载
- 积分：1
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chudeng
一个介绍matlab的课件，介绍初等模型的，相信对大家都有用处的，很好的课件。(An introduction matlab courseware to introduce elementary model, I believe we have useful, well courseware.)
- 2010-07-27 16:41:55下载
- 积分：1
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d2conv
二维信号卷积，若x为N1*M1的二维信号，y为N2*M2的二维信号，则卷积为(N1+N2-1)*(M1+M2-1)的信号(Two demension signal convolution. )
- 2014-08-21 12:41:40下载
- 积分：1
