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MATLAB-Wavelet-transform

于 2021-01-30 发布 文件大小:103KB
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  Matlab小波变换与傅立叶变换用于检测阶跃信号,原始时域信号是一个阶跃信号,为了确定阶跃信号的突变点,分别采用傅立叶变换和db5小波进行处理。(Matlab wavelet transformation and Fourier transform is used to test signal, the original order jump time signal is a step road signal, in order to determine the Laplace domain signals point mutations, respectively the Fourier transform and db5 wavelet for processing. )

文件列表:

时频分析2.doc,135680,2011-09-28

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  • 201312456
    本程序采用遗传算法接力进化,子函数和主函数不要放在一起,子函数另外作为一个M文件,运行主函数。多次运行主函数,直到达到误差满意的效果。(This procedure using genetic algorithm (ga) relay evolution, function and main function don t together, and function of the file as a M, run the main function. Run several times the main function, the error until you reach satisfactory results. )
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  • chengxu
    小波变换进行变速箱故障诊断 首先将s1和s2信号时域谱(s1代表维修前的振动信号,s2代表维修后的振动信号),画出来进行对比,会发现s1信号的振动幅值会比较高;然后对s1和s2分别进行小波分解并画出各层的时域谱,只对比s1和s2分后的最高时域谱,s2更加的具有周期性,且幅值较小,s2周期性不够明显,且振动过于密集。分析完时域谱后开始分析频谱,首先对原信号s1和s2fft转换,得到频谱图,如图,然后再对小波分析后高频部分进行fft转换,做出频谱图。对比后我们发现,在f 2375HZ出(也就是齿轮的啮合频率),s1信号频谱幅值会有急剧的升高,然后,其谐波的幅值也会增大。所以可以推断出该维修前的增速箱的齿轮可能出现问题。(Gearbox fault diagnosis based on wavelet transform s1 and s2 first time domain signal spectrum (s1 behalf of the vibration signal before maintenance, vibration signal s2 representative of repaired), drawn comparison, you will find a signal s1 vibration amplitude will be higher then s1 and s2 respectively wavelet decomposition and draw the layers of time-domain spectrum to only a maximum time domain spectroscopy s1 and s2 points after, s2 is more cyclical and smaller magnitude, s2 cyclical enough obviously, and the vibration is too dense. End domain spectral analysis after the beginning of the spectrum analysis, the first of the original signal s1 and s2fft conversion to give the spectrum, as shown, and then after the high frequency part of wavelet analysis fft transformation to make spectrum. We found that after the comparison, at f 2375HZ out (i.e. the gear mesh frequency), there will be a sharp increase in the amplitude spectrum of the signal s1, and then, the amplitude of the ha)
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