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B06040324_B2
模拟电信计费系统的设计与实现
要求：（1） 计费功能。根据存放在源数据文件中的通话记录和长途费率文件对每一条通话记录计算其通话费用，并将结果保存在费用文件中。其中：
通话费的计算方法如下：
通话费＝长途电话费＋本地电话费
长途电话费＝费率（元/分钟）×通话时长（分钟）
(通话时长不满1分钟的按1分钟计算)
本地电话费为：3分钟以内0.5元，以后每3分钟递增0.2元。
（2） 话费查询。输入一个电话号码，从费用文件中统计该电话号码的所有本地话费、长途话费，并从用户文件中查找其用户名，最后在屏幕上显示：
用户名 电话号码 本地话费 长途话费 话费总计
（3） 话单查询。输入一个电话号码，查询并在屏幕显示该用户的所有通话记录，格式为：
用户名 主叫电话号码 被叫电话号码 通话时长
(Design and implementation of simulation of telecommunication billing system
Requirements: (1) the charging function. According to the calculation of the call charges stored in the source data file in the call records and the long rate documents for each call record, and save the results in cost file. Among them:
The following conversation method to calculate the fee:
Long distance telephone calls =+ local telephone fee
Long distance telephone fee = rate (yuan/minute)* call time (minutes)
(call time less than 1 minutes to 1 minutes)
Local call: 3 minutes 0.5 yuan, increasing 0.2 yuan every 3 minutes later.
(2) calls inquiries. Enter a phone number, all local calls, long-distance calls statistics the phone number from the cost in the file, and find the user name from user file, and finally displayed on the screen:
The user name phone number local calls long distance charges charges totaling
(3) if a single query. Enter a phone number, query and display all the call records of th)
- 2013-09-25 05:53:29下载
- 积分：1
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shiper
Воронежский гос университет, задача по сям
- 2009-10-11 01:30:49下载
- 积分：1
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jiaobingbu
集合的运算：交、并、补（难度系数：1.1）
全集：大写字母 ‘A’~’Z’
要求实现以下功能：
1、集合的输入：自动去掉重复和非法的字符
2、集合的显示：输出集合的全部元素
3、输出一个给定集合的补集
4、输出两个给定集合的交集和并集
(jiao bing bu)
- 2013-11-29 20:49:25下载
- 积分：1
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Desktop
调度问题的回溯算法，算法中的经典问题。问题描述：假设有n个任务由k个可并行工作的机器完成。完成任务i需要的时间为ti。试设计一个算法找出完成这n个任务的最佳调度，使得完成全部任务的时间最早。(Scheduling problem backtracking algorithm is the classic problem. Problem Description: Suppose there are n-task by the k-parallel machine can be completed. The time required to complete the task i is ti. Try to design an algorithm to find completing these n-best task scheduling, making the earliest time to complete all tasks.)
- 2010-02-19 23:31:11下载
- 积分：1
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CProgram.rar
说明： 实现了很多的数据结构算法，适合与想学习数据结构编程的读者。(achieve a lot of data structure algorithms, fit and want to learn data structure programming readers.)
- 2006-04-05 16:52:57下载
- 积分：1
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StringDataManage
控制台下的字符串管理程序，并且带有好看的节面（使用其他人的库）(String under the console management program, and with a good-looking face of the section (using other people s libraries))
- 2012-11-22 01:26:14下载
- 积分：1
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Triangle
求解符号三角形问题.给定一行符号(比如+和-),按照同号为+异号为-的原则计算第二行直至下面的行,最后的一行只有一个符号,要求统计各个符号的个数.(Problem solving triangle symbols. Given his symbols (such as+ And-), in accordance with the same number is+ Different number- the principle of calculation of the second line until the following line, the last line there is only one symbol, all symbols requested statistics number.)
- 2008-07-15 14:53:58下载
- 积分：1
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medo
设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组，每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。 编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n（n<=200），表示每个数组有n个数。接下来的两行分别是X，Y数组的元素。结果输出 程序运行结束时，将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits. programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)
- 2021-03-22 16:29:16下载
- 积分：1
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tongxinlu
通信录源程序。调试环境为TC2.0或者3.0。运行这个程序需要tc提供的几个头文件。(Example source address book, or 3.0 debugging environment for TC2.0. Tc run the program needs to provide several header files.
)
- 2011-12-05 15:03:16下载
- 积分：1
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b64
base64 decoder to decode the original char from base64 encoded string(base64 decoder)
- 2009-07-17 11:03:47下载
- 积分：1
