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ma1104
说明： 利用最速下降法的3输入2使出的BP网络，可以快速的得到训练结果(Steepest descent method using 3-input 2 resorted to the BP network, the result can be trained quickly)
- 2011-04-13 07:13:17下载
- 积分：1
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OFDM1
代码主要是基于matlab的OFDM程序(Code is mainly based on the OFDM matlab program)
- 2011-04-27 20:59:16下载
- 积分：1
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Smart_antenna_System
关于智能天线系统的matlab仿真源程序。(smart antenna systems Matlab simulation source.)
- 2006-07-28 12:02:00下载
- 积分：1
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diabetes
extreme learning machine 例子
run sinc_mean
(extreme learning machine examples run sinc_mean)
- 2007-12-16 22:59:10下载
- 积分：1
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proj03_03
homework 3-3 is difficult
- 2011-11-09 18:55:22下载
- 积分：1
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code
稀疏傅立叶算法，matlab实现仿真，对于算法重构用到了混叠同余法和相位解码法，并对SFFT和FFT算法对同一数据的处理时间进行了对比。(Sparse Fourier algorithm, matlab to achieve the simulation, the algorithm used for aliasing congruence and phase decoding method, and the SFFT and FFT algorithm for the same data processing time were compared.)
- 2021-03-18 18:09:19下载
- 积分：1
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geomorphologicalremotesensingclassificationwithmat
geomorphological remote sensing
classification by matlab from CUP
- 2008-06-12 08:50:04下载
- 积分：1
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rumen
matlab入门与提高的例子与源程序。希望大家好好学习呀、。(Getting Started with the matlab example to increase with the source.)
- 2009-06-08 22:34:25下载
- 积分：1
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ExtendedKalmanFilter
Extended Kalman Filter Tracking Object in 3-D(Assume that we want to track an object moving in 3-D space with constant velocity. Our instruments observe bearing, range and high(cylindrical coordinates). However, of an interest are rectangular coordinates. Since transformation is non-linear this requires use of extended Kalman filter.
Because transformation is non-linear between X,Y and Range,Bearing and linear between Z and high(Z is height), this problems serves as a good comparason of how well extended Kalman filter can perform. By comparing its linear estimation error in Z to non-linear estimations in X and Y, we can judge how non-familiarities effect estimation. )
- 2012-05-14 22:14:04下载
- 积分：1
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example2
利用遗传算法求f(x,y)=x*cos(2*pi*y)+y*sin(2*pi*x),-2<=x<=2,-2<=y<=2的最大值(Using genetic algorithms for f (x, y) = x* cos (2* pi* y)+ y* sin (2* pi* x),- 2 <= x <= 2,-2 <= y <= 2 the maximum)
- 2014-10-01 09:22:24下载
- 积分：1
