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matlab
对流体数及设置颜色，添加切片，顶光效果的设置等等(Number of fluid and set the color, add the slices, top light effect settings, etc.)
- 2011-05-16 10:09:11下载
- 积分：1
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figner_IMcode_mfile
指纹识别的一套完整成，还有指纹图像。绝对有用，适合毕业设计研究(Into a complete fingerprint recognition, as well as the fingerprint image. Definitely useful for the design of graduation)
- 2010-05-06 23:15:57下载
- 积分：1
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Particle Filturing
粒子群滤波算法及改进算法代码，包含代码说明(Particle swarm optimization algorithm and improved algorithm code, including code description)
- 2020-10-26 15:19:59下载
- 积分：1
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LaubARE_SchurMethod.pdf
这是一个里卡迪方程的简易对角线解法，有一定的现实意义，可以在matlab的计算里减少很大的计算量。十分好用(This is a simple solution Ricadi diagonal equation, there are certain practical significance, can reduce a large amount of computation in the calculation in matlab. Very easy to use)
- 2014-08-08 22:17:09下载
- 积分：1
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dispersion
对光纤传输系统中的色度色散进行了仿真，超级正确(pair of optical fiber transmission system of chromatic dispersion for simulation, the Super correct)
- 2006-09-27 18:42:24下载
- 积分：1
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F16fcs_10V1
一些控制方面的东西 希望对大家能有用 希望大家能多上传一些有关飞行控制的东西啊
(Some control of things we hope to be useful for and I hope people can up down more useful code about control)
- 2011-06-14 22:51:55下载
- 积分：1
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Matlab
matlab 智能计算 算法 详细 (matlab suan fa xiang xi)
- 2011-10-26 12:31:06下载
- 积分：1
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qunbang_v38
FIR 底通和带通滤波器和IIR 底通和带通滤波器，多姿态，多角度，有不同光照,抑制载波型差分相位调制，这个有中文注释，看得明白，均值便宜跟踪的示例，使用大量的有限元法求解偏微分方程，感应双馈发电机系统的仿真，包含了阵列信号处理的常见算法。
( Bottom-pass and band-pass FIR and IIR filter bottom pass and band-pass filter, Much posture, multi-angle, have different light, Suppressed carrier type differential phase modulation, The Chinese have a comment, understand it, Example tracking mean cheap, Using a large number of finite element method to solve partial differential equations, Simulation of doubly fed induction generator system, Contains a common array signal processing algorithm.
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- 2017-04-06 22:24:10下载
- 积分：1
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nmodeproduct
说明： 在Matlab中计算一个张量和一个矩阵的mode-n（模n）乘积，相关运算原理请查找相关教材。(This matlab file can culculate the mode-n product of a tensor and a matrix.)
- 2020-04-06 21:37:40下载
- 积分：1
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fft_1
已知两个序列x[n]=cos(n*pi/2), y[n]=ej*pi*n/4x[n],绘制X(ejw)和Y(ejw)和幅度和相角,说明它们的频移关系(The known two sequence x [n] = cos (n* PI/2), y [n] = ej* PI* n/4 x [n], draw x (ejw) and y (ejw) and amplitude and phase Angle, suggesting their frequency shift relationship
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- 2012-04-24 20:17:48下载
- 积分：1
