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ZF-MMSE
VBLST译码算法仿真源程序
代码包括了常用的调制和解调方式。(Simulation VBLST source decoding algorithm)
- 2009-05-26 16:20:31下载
- 积分：1
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Comp-Ocr
Optical Charactor Recognition
- 2013-07-27 03:50:08下载
- 积分：1
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PSO-Fuzzy-Modeler-Mamdani-for-charger
PSO Fuzzy Modeler (Mamdani) for charger
- 2013-12-09 08:01:47下载
- 积分：1
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matlab-videoread
用matlab进行视频读取的程序，并附有c语言程序，很有价值。(Using matlab to read the procedures for video, together with c language program, very valuable.)
- 2008-12-16 19:58:24下载
- 积分：1
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2008102116273584909
数字通讯原理及通讯计算方式！！！！！！！！(Digital communication theory and communication formula! ! ! ! ! ! ! !)
- 2010-07-11 23:23:04下载
- 积分：1
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OFDM
正交频分复用（OFDM）的调制与解调以及OFDM的误码率。(Orthogonal Frequency Division Multiplexing (OFDM) modulation and OFDM demodulation and bit error rate.)
- 2010-05-12 14:48:48下载
- 积分：1
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zernike_radial_polynomials
An iterative QuRecursive method (using q-recursive) to generate Zernike
- 2012-05-03 15:23:24下载
- 积分：1
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2
说明： matlab科学计算的几乎所有数学算法以及仿真。每一个m文件在我学习的时候都验证了其正确性。前面的比较简单，逐步深入。另外对部分算法本人在学习中做了优化，更简洁。(matlab scientific computing almost all mathematical algorithms and simulation. M each file in my learning at all times to verify its correctness. In front of a relatively simple step by step in depth. In addition to some algorithm I have done a study of optimization, a more concise.)
- 2008-12-25 16:23:52下载
- 积分：1
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10000bitsbipolar
说明： 产生一个10000位的bipolar信号并画出bit error performance的模拟图像，求出BER(The source generates equally probable bits, P(0) = P(1) = 0.5.
(a) Construct a program to generate 10000 bits with bipolar signaling.
(b) Use your program to simulate the bit error performance of the system with
Eb/N0 = 0, 2, 4, 6, 8, 10 dB.
(c) Compare your simulated performance with the analytical expression for the
bit error rate (BER):)
- 2011-02-23 09:06:18下载
- 积分：1
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equal-area-critirea
E=input( enter the generator voltage: )
V=input( enter the infinite bus voltage: )
Gx=input( enter the reactance of generator: )
L1x=input( enter the line reactance: )
L2x=input( enter the line reactance: )
L3x=input( enter the line reactance: )
L4x=input( enter the line reactance: )
Pi=input( enter the input power: )
X1=Gx+L1x+((L2x*L3x)/(L2x+L3x))+L4x
Pm1=E*V/X1
DO=asin(Pi/Pm1)
A=((L2x*L3x)/(2*(L2x+L3x)))
C=A
B=((L3x/2)^2)/(L2x+L3x)
X2=(Gx+L1x+A)+(L4x+A)+(Gx+L1x+A)*(A+L4x)/B
Pm2=(E*V)/X2
X3=Gx+L1x+L2x+L4x
Pm3=(E*V)/X3
DC=input( enter the fault clearing angle: )
Dm=(3.14-asin(Pi/Pm3))
a1=quad( sin ,DO,DC)
A1=(Pi*(DC-DO)-Pm2*a1)
a2=quad( sin ,DC,Dm)
A2=Pm3*a2-Pi*(Dm-DC)
if(A2>=A1)
disp( the system is stable )
else
disp( the system is unstable )
end
Dcc=acos((Pi*(Dm-DO)-Pm2*(cos(DO))+Pm3*(cos(Dm)))/(Pm3-Pm2))
disp( critical clearing angle: )
Dcc
- 2012-09-11 22:46:05下载
- 积分：1
