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15883875matlab-communication
this is matlab souce code with commication subject. it is good for others.
- 2009-03-22 05:20:56下载
- 积分：1
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New-folder-(5)
energy detector for spectrum sensing for cognitive radio
- 2012-05-07 06:43:56下载
- 积分：1
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commfreqsyn
锁相频率合成器的simulink模型，可验证电路设计的工作过程和合理性。(Phase lock loop)
- 2015-02-02 14:51:26下载
- 积分：1
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aCyl_en
Cylindrical dielectric resonator analysis
- 2013-01-30 07:04:25下载
- 积分：1
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navigation
Ship navigation project
- 2014-12-04 18:58:16下载
- 积分：1
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graph
建模大赛城市表层土壤重金属污染分析试题图形与函数绘制(Modeling Contest heavy metal pollution of urban topsoil graphics and function draws questions)
- 2013-09-21 08:47:06下载
- 积分：1
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exploreRGB
Explore RGB using MAtlab program.
Useful to extract the information based on the image
- 2010-12-26 13:46:44下载
- 积分：1
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relaxed-newton
采用一种松弛牛顿法，对IEEE33节点系统进行潮流计算，并得出正确结果。(Newton s method uses a relaxation programming for IEEE33 node system and derive the correct results)
- 2014-10-31 14:11:50下载
- 积分：1
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mateda2.0
说明： 分布估计算法的MATLAB工具箱，EDAs工具箱(Estimation of distribution algorithms in MATLAB toolbox, EDAs Toolbox)
- 2020-11-13 16:29:43下载
- 积分：1
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simulation
在一个移动通信系统中，发射信号是一个未调制的音频x(t)=cos(2πft)，其中f=f0+fi。设标称载波为f0=1GHz，并设fi =512Hz。假定移动用户在一个繁忙的高速公路上距离基站l公里处的地方，从开始从每小时60公里的速度开始，其速度（在0.01秒的时间间隔内测量）以1/2的概率随机的增加或减少1/10公里每小时。试仿真移动用户在这2s的时间间隔内所接收到的信号(及其频谱)。接收信号可以表示为：
y(t)=a(t)Cos[2π(fo+f1)(t-△t)]
式中 △(t)=d(t)/c
且 a(t)=k/d2(t)
在上面的表达式中d(t)是在t时刻基站与移动用户的距离，c是光速，△(t)是传播延迟，而a(t)是信号在t时刻的衰减，并假设在这2s内a(t)是一个常数。利用复低通等效模型来进行仿真。(In a mobile communication system, the transmitted signal is an unmodulated audio x (t) = cos (2πft), where f = f0+ fi. Let nominal carrier of f0 = 1GHz, and set fi = 512Hz. Assume that mobile users on a busy motorway station l kilometers place, starting the beginning of 60 kilometers per hour, the speed (measured in 0.01 second interval) to increase the probability of a random 1/2 or reducing 1/10 km/h. Simulation test signal which the mobile subscriber in the 2s time intervals of the received (and its spectrum). The received signal can be expressed as:
y (t) = a (t) Cos [2π (fo+ f1) (t- △ t)]
Where △ (t) = d (t)/c
And a (t) = k/d2 (t)
In the above expression, d (t) at time t is a base station and a mobile user s distance, c is the speed of light, △ (t) is the propagation delay, and a (t) is the attenuation of the signal at time t, and assuming that 2s within a (t) is a constant. Using complex low-pass equivalent model for emulation.)
- 2015-11-24 17:16:20下载
- 积分：1
