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displacement

于 2010-05-28 发布 文件大小:2KB
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代码说明:

  有n个整数,使其前面各数顺序向后移m个位置,最后m个数变成最前面的m个数 (There are n integers, the number of its previous order of the backward shift m positions, the last m number of m into the number of front )

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