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FastICA_23
fastICA完整matlab代码，有详细fastICA算法代码介绍(fastICA complete matlab code, a detailed description fastICA algorithm code)
- 2010-06-03 22:14:02下载
- 积分：1
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rayleigh_matlab
无线通信系统中在rayleigh衰落信道下的matlab仿真源程序(wireless communication system in rayleigh fading channel simulation source of Matlab)
- 2007-03-17 16:57:48下载
- 积分：1
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nongcun
本例程模拟的是额定电压为10kV的单相输电系统. 其主要参数如下：线路首端电压的仿真模块VS电压为14.847kV；电压源等效内阻Rs_eq为 ；相位：0；频率：50Hz；输电线路用 型等效线路替代，线路长度 ；用户端为恒定负荷1000kvar(The main parameters of this paper are as follows: The VS voltage is 14.847kV the equivalent internal resistance Rs_eq of the voltage source is Phase: 0 Frequency: 50Hz Transmission Line-type equivalent line replacement, line length client-side constant load 1000kvar)
- 2017-02-10 08:30:03下载
- 积分：1
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test-lms
自适应信号处理，最终的权值矩阵就是滤波器的系数，学习曲线描述其收敛特性(Adaptive signal processing, the final weight matrix is the filter coefficient, the learning curve to describe the convergence properties)
- 2008-06-04 09:27:07下载
- 积分：1
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matlab_pwelch_windows
采用加窗法在matlab中进行功率谱密度计算(Windows and method for power spectral density calculation in matlab)
- 2014-10-26 12:11:33下载
- 积分：1
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多假设跟踪Matlab代码MHT
多假设跟踪Matlab代码例子,也是从别的地方下载的(example of MHT target tracking)
- 2020-07-19 15:48:48下载
- 积分：1
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Calc_kerls
volterra series 核函数 matlab 程序(volterra series kernel)
- 2021-02-20 21:09:42下载
- 积分：1
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DrawTest_2.0.2.tar
制作出来的显示界面，有坐标，相关显示波形(Produced the display interface, with coordinates, related to the waveform display)
- 2010-07-14 14:59:07下载
- 积分：1
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DWT
此代码为多分辨率小波变换，可对原始信号进行多尺度分解(This code for multi-resolution wavelet transform, the original signal can be multi-scale decomposition)
- 2014-10-21 20:26:56下载
- 积分：1
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pi_method1
Estimated number of Pi ( Method 1)
how do we estimate Pi by simulation? In the simulation, you keep throwing darts at random onto the dartboard. All of the darts fall within the square, but not all of them fall within the circle. Here s the key. If you throw darts completely at random, this experiment estimate the ratio of the area of the circle to the area of the square, by counting the number of darts in each.
Our study of the geometry tells us this ratio is Pi/4. So, now we can estimate Pi as
- 2013-04-29 02:49:47下载
- 积分：1
