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zernikepol
zernikepol多项式函数zernikepol多项式函数zernikepol多项式函数zernikepol多项式函数zernikepol多项式函数zernikepol多项式函数(zernikepolzernikepolzernikepolzernikepolzernikepolzernikepolzernikepolzernikepolzernikepolzernikepolzernikepolzernikepol)
- 2010-07-07 15:56:38下载
- 积分:1
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AlgorithmsForProgrammersIdeasAndSourceCode
Algorithms For Programmers Ideas And Source Code英文的,希望对大家有帮助。()
- 2007-09-17 08:51:58下载
- 积分:1
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mseFea
multi-view spectral learning
- 2010-11-12 20:48:28下载
- 积分:1
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maxcost
“基于Floyd最短路算法的Ford和Fulkerson迭加算法”的最小费用最大流算法,其基本思路为:把各条弧上单位流量的费用看成某种长度,用Floyd求最短路的方法确定一条自V1至Vn的最短路;再将这条最短路作为可扩充路,用求解最大流问题的方法将其上的流量增至最大可能值;而这条最短路上的流量增加后,其上各条弧的单位流量的费用要重新确定,如此多次迭代,最终得到最小费用最大流。
(" Floyd shortest path algorithm based on the Ford and Fulkerson algorithm superposition" of the minimum cost maximum flow algorithm, the basic idea is: the flow of each arc on the unit cost as a length, with Floyd for the most short-circuit method to determine a from V1 to Vn of the most short-circuit then this can be expanded as the shortest way, by solving the maximum flow of traffic on the way to its maximum possible value and this increased the flow of the shortest path, on which the arcs of the unit to re-determine the cost of traffic, so several iterations, finally get the minimum cost maximum flow.)
- 2010-12-22 17:27:32下载
- 积分:1
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CNsolution_3---Copy
Solutions for communication networks 3.(Solutions for communication networks 3. Good for students to understand exercises in the book.)
- 2013-11-07 04:33:47下载
- 积分:1
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IEEEdata3
IEEE节点测试数据大全,很全面的资料,参考价值大(The IEEE data Guinness, comprehensive information)
- 2012-10-04 15:11:32下载
- 积分:1
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HWmatrix
实现图像的霍夫曼编码和解码,用MATLAB(Huffman coding and decoding to realize image)
- 2020-10-31 19:59:55下载
- 积分:1
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pilot-db
embedded db for PALM
- 2009-11-25 18:12:30下载
- 积分:1
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Rotation
matlab应用程序可以实现图像的修正,可以使用。(matlab application images can be amended, you can use.)
- 2009-06-08 22:31:13下载
- 积分:1
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deceptionjammer
合成孔径雷达欺骗式干扰的matlab仿真源码(Synthetic aperture radar deception matlab simulation-type of interference source)
- 2009-06-13 22:55:12下载
- 积分:1