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recursion
说明： 递归，是函数实现的一个很重要的环节，很多程序中都或多或少的使用了递归函数。递归的意思就是函数自己调用自己本身，或者在自己函数调用的下级函数中调用自己。
递归之所以能实现，是因为函数的每个执行过程都在栈中有自己的形参和局部变量的拷贝，这些拷贝和函数的其他执行过程毫不相干。这种机制是当代大多数程序设计语言实现子程序结构的基础，是使得递归成为可能。(Recursion, is a function to achieve a very important part of many programs are more or less use the recursive function. Recursive mean that the function of its own call to themselves or subordinates in their own function calls a function to call their own. Recursion that can be achieved because the function of each execution in the stack has its own shape parameters and local variables of the copy, the copy and the implementation process has nothing to do other functions. This mechanism is the most modern programming language implementation subroutine structure of the foundation is to make recursion possible.)
- 2009-08-30 16:26:06下载
- 积分：1
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shengyazhuanhuan
用于进行声压转换的matlab文件，声压数据来源于ansys软件的计算后导出来的。(Used for sound pressure to convert matlab file, sound pressure data from the calculation software ansys guide out.)
- 2013-09-26 09:10:30下载
- 积分：1
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chap4
胡晓东，董辰辉.MATLAB从入门到精通[M]的m文件(Hu Xiaodong, Dong Chen-hui. MATLAB from entry to the master [M] m-file)
- 2011-07-27 18:07:16下载
- 积分：1
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915M-uhf
这是通过hfss软件设计915m超高频偶极子天线工程 此设计只通过仿真验证 没有制作实物验证(It is designed to 915m UHF dipole antenna hfss software engineering through the design just does not make physical verification by simulation)
- 2013-12-29 10:53:39下载
- 积分：1
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Clipboard02
This application show how to Copý the entire contents of an multiline edit control to Clipboard and paste into another control.
- 2015-03-15 17:36:40下载
- 积分：1
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xppaut_latest.tar
XPPOUT latest, Window GUI
- 2015-09-09 13:33:07下载
- 积分：1
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Vcmatlabsrc
matlab和vc++联合编程的例子，使用matcom编写matlab程序链接成库文件在vc++中使用。(matlab and vc++ joint programming examples, the use of matlab Matcom preparation procedures into a library file in the link vc++ use.)
- 2008-07-30 20:46:50下载
- 积分：1
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momh_effectiveness_mopgp
MOEAs对于度欧表的有 花纹那(MOEAs for the degree of European tables have patterns that)
- 2008-05-31 16:26:10下载
- 积分：1
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beibaowenti
有N件物品和一个容量为V的背包。第i件物品的费用是c，价值是w。求解将哪些物品装入背包可使这些物品的费用总和不超过背包容量，且价值总和最大。(There are N items and a knapsack capacity of V' s. No. i is the cost of items c, the value of w. Solving items into the backpack which will enable the cost of these items does not exceed the sum of the capacity of backpack, and the sum of the maximum value.)
- 2009-05-07 22:10:10下载
- 积分：1
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GA
说明： 关于GA的c++代码和matlab代码的一个文件，可以做一个性能对比后，选择使用(On GA in c++ code and matlab code of a file, you can make a performance comparison, the option of using)
- 2010-06-01 15:29:19下载
- 积分：1
