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Xflow13
image processing Xflow
- 2010-08-28 15:40:38下载
- 积分：1
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ICAforspeech
几路语音信号的盲源分离，采用FDICA，有图形化界面，特别适合中级学者(Several road blind source separation of speech signals, using FDICA, a graphical interface, especially for intermediate and scholars)
- 2010-08-30 15:26:06下载
- 积分：1
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OFDMA_Data_mapping_Downlink
OFDMA Data mapping Downlink
- 2011-05-12 16:21:47下载
- 积分：1
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nervous
根据滚动轴承的内圈，外圈，滚动体，正常四方面做故障诊断预处理(According to the fault of rolling bearing inner ring, outer ring, rolling body, the normal four fault diagnosis pretreatment)
- 2015-03-31 14:28:37下载
- 积分：1
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EZWcode
嵌入式小波零树（EZW）算法的过程详解和Matlab代码。(EZW code 。)
- 2009-04-03 19:12:51下载
- 积分：1
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chapter2
张德丰matlab小波分析源代码，从信号时-频联合分析引入小波变换，将信号的多分辨率分析及Mallat算法作为全书的重点，并在此基础上，进一步阐述了双正交小波多分辨率分析、小波包多分辨率分析、提升小波应用，还讲述了小波分析在奇异性检测、去噪及数据压缩中的应用。(Zhang Defeng Matlab wavelet analysis of the source code from the signal- frequency joint analysis of the introduction of wavelet transform, multi-resolution analysis of the signal and Mallat algorithm as the focus of the book, and on this basis, further elaborated biorthogonal wavelet multi-resolution analysis wavelet packet multi-resolution analysis, the lifting wavelet applications, but also about the application of wavelet analysis in the singularity detection, de-noising and data compression.)
- 2013-05-21 18:55:10下载
- 积分：1
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Digital_Audio
实现数字音频效果的源程序，包含多速率信号处理的内插和抽取源程序。(realize the audio effect.inlude the function of multirate signal processing knowledge)
- 2009-03-04 19:36:08下载
- 积分：1
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glpj
基于MATLAB高通低通滤波器源程序,很详细的源程序，有注释的哦！(good and Strong！you will like it!if you fell good ,please support me!)
- 2010-05-23 10:27:01下载
- 积分：1
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spectral-nana
三电平同相层叠PWM方法谐波频谱分析及滤波器设计(Cascade three-level PWM method compared with the harmonic spectrum analysis and filter design)
- 2011-09-01 14:56:42下载
- 积分：1
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base
1.分别在两个图中画出δ(n)和δ(n-2)，其中-10≤n≤10，画出U（n）其中-10≤n≤10。
2.分别在两个图中画出x1(n)=cos(2π×20×0.01×n)，0≤n≤10和x2(n)=(0.8)n，1≤n≤6。
3.由上一题，计算y(n)=x1(n)+x2(n)，并画图。(1. Draw the figure at two δ (n) and δ (n-2), where-10 ≤ n ≤ 10, draw the U (n) where-10 ≤ n ≤ 10. 2. Respectively in the two Draw the figure x1 (n) = cos (2π × 20 × 0.01 × n), 0 ≤ n ≤ 10 and x2 (n) = (0.8) n, 1 ≤ n ≤ 6. 3. from the previous question, calculate y (n) = x1 (n)+ x2 (n), and drawing.)
- 2010-11-26 16:34:06下载
- 积分：1
