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ecc_matlab

于 2012-03-24 发布 文件大小:139KB
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下载积分: 1 下载次数: 42

代码说明:

   This is a demo execution of ECC image alignment algorithm comment two of the three following lines transform = translation transform= affine transform = homography YOU MIGHT NEED MORE ITERATIONS FOR HOMOGRAPHIES!

文件列表:

cameraman.tif,65126,2012-02-10
ecc.m,11153,2012-02-12
ecc_demo.m,4265,2012-02-12
image.pgm,65551,2012-02-12
image_jacobian.m,1216,2012-01-10
next_level.m,1902,2012-01-10
param_update.m,1251,2012-01-10
README.txt,1100,2012-02-12
spatial_interp.m,2281,2012-01-10
template.pgm,46671,2012-02-12
warp_jacobian.m,2221,2012-01-10

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    说明:  给定n种物品和一个背包,物品i的重量是Wi,价值是vi,被包容量是C,应该如何选择装入被包的物品,使得装入背包中物品的总价值最大?对于每种物品i,只有两种选择,装入或者不装入. 输入:第一行两个正整数n(物品数)和C(容量) 第二行n个正整数n,表示物品价值 第三行n个正整数n,表示物品重量 输出:第一行表示总价值 第二行n个数(0/1),0表示物品不装入,1表示装入 例如, 输入: 5 10 6 3 5 4 6 2 2 6 5 4 输出 15 1 1 0 0 1 (Species of a given n items and a backpack, the weight of item i is Wi, the value of vi, was packet capacity is C, should be how to choose a package of items to be loaded, the backpack load in the largest total value of goods? For each item i, there are only two options, loaded or not loaded. Input: the first line of the two positive integer n (the number of items) and C (capacity) of the second line of n positive integer n, that the value of the third line of n positive integer n, that the weight of output: the total value of the first line of the second line, said n number of (0/1), 0 that the items do not load, that load 1 for example, enter: 5,106,354,622 6 5 4 output 15 1 1 0 0 1)
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