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pca_regression
基于主元分析的多元线性回归程序,输出回归系数，主元贡献率和拟合误差(multiple linear regression using pca)
- 2009-03-31 21:34:36下载
- 积分：1
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nrlfppg
NEWTON RAPSHON METHOD FOR LOAD FLOW
- 2014-08-18 00:22:20下载
- 积分：1
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LipingJi1SA
Implementation of LipingJi s paper
A Novel Covert Channel Based on Length of Messages
Steganography.
- 2014-11-12 16:08:15下载
- 积分：1
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SWIII
Swerling case three radar target
- 2012-01-31 00:14:40下载
- 积分：1
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IntegrodifferentialOperator
M file of Matlab code (integro differential of iris ) .
- 2010-10-19 03:58:30下载
- 积分：1
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model8b
数学建模清华数模讲义\model8b (Mathematical modeling Qinghua digital-analog handouts model8b)
- 2010-01-13 23:25:08下载
- 积分：1
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picedit
说明： (1) 條碼掃描槍 (1個): 用於刷證件Barcode(條碼)
(2) 鐳射列印機 (1台): 用於列印證件(型號: Epson stylus C67)
(3) 攝像頭 (1個): 用於攝制來賓照片
((1) bar code scanner (1): for Brush documents Barcode (Barcode) (2) laser printer (1 unit): used to print documents (Model: Epson stylus C67) (3) camera ( 1): for shooting photos guests)
- 2010-04-29 12:32:50下载
- 积分：1
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4d1112
减摇水舱对船舶参数横摇的抑制，4自由度模型，包括垂荡‘纵摇和水舱状态(The anti rolling tank on the inhibition of Parametric Rolling of ships, model of 4 degrees of freedom, including heave pitching and water tank to state
)
- 2020-09-25 18:27:47下载
- 积分：1
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dsk05
信号处理书中所附光盘，包括各个章节，很全，大部分能直接拿来用，很实用(The book accompanying CD-ROM signal processing, including various chapters, it is the whole, most can be brought directly to use, very practical)
- 2009-09-25 00:25:48下载
- 积分：1
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fano
设有离散无记忆信源X,P(X)．二进制费诺编码为：1.将信源符号按概率从大到小的顺序排列2.将信源分成两组――按两组概率之差为最小分．3.上面一组编码为0，下面一组编码为1，一直分到一组只有一个信源为止．4.将一个信源分组得到的0和1全部连接起来，组成该信源的码字，信源即得到自己的费诺编码．(There be no X remembering the message source in case that having being scattered, binary Feinuo of P (X) code is: 1. Will believe that the source sign orders 2 according to probability is minor from arriving at greatly sequence. Will believe that the source divides into two part being allotted 3 according to two set of bad of probability for the minimum. A group of code is 0 above , a group of code is 1 underneath, till dividing till a group only when one believes a source 4. Get up with a 0 and 1 all connection believing that the source is divided into groups and , be composed of the codon owing message a source , believe that the source is to get self Feinuo code
Powered )
- 2009-11-27 12:04:44下载
- 积分：1
