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maze
说明: 由数字1和0组成迷宫,0代表可走路径,程序会用坐标的形式给出每一步的走法(Composed by a maze of numbers 1 and 0, 0 to go the path, the program will use the coordinates given in the form of moves at each step)
- 2011-03-27 20:57:47下载
- 积分:1
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FreeTree
无环连通图G=(V, E)亦称为自由树T,其直径是树中所有顶点之间最短路径的最大值,设计一个算法求T的直径(Acyclic connected graph G = (V, E) is also known as free tree T, whose diameter is the tree of shortest paths between all vertices maximum design an algorithm for the diameter of T)
- 2013-10-29 16:31:47下载
- 积分:1
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ok-suit
说明: 一个实现外部排序的程序,其中gnerate.cpp为产生一个随机的文件,用于被排序。而caculate.cpp为外部排序程序。(A realization of the external sort program, which gnerate.cpp to generate a random file for be sorted. The caculate.cpp external sort program.)
- 2011-03-18 12:30:29下载
- 积分:1
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luciferLanguage
这是acm里关于魔王语言的一道题,通过栈和队列的知识来解决。(this is balout luciferlanguage . i use the datastructure with stack and queue.)
- 2011-11-28 17:04:19下载
- 积分:1
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NewCode
清(英文)常见数据结构,代码实现,值得下载,值得分享(Qing (English) common data structure, code implementation, worth downloading, worth sharing)
- 2012-11-21 14:33:49下载
- 积分:1
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Huffman
说明: 数据结构:Huffman编码。哈夫曼编码是哈夫曼树的一个应用。哈夫曼编码应用广泛,如JPEG中就应用了哈夫曼编码。 哈夫曼树又称最优二叉树,是一种带权路径长度最短的二叉树。(Data structure: Huffman coding. Huffman coding is an application of the Huffman tree. Huffman coding is widely used, such as JPEG in the application of the Huffman coding. Huffman tree, also known as the best binary tree is a weighted shortest path length binary tree.)
- 2011-03-29 22:44:59下载
- 积分:1
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第4章
清华大学出版社,数据结构简明教程李春葆著,第四章源文件(Tsinghua University press, a brief course on data structure, Li Chunbao, fourth chapters)
- 2018-02-03 14:39:12下载
- 积分:1
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HuffmanTree
用c++实现的haffman tree 小程序,仅供参考 。 (The the haffman tree applet realized with c++ for reference only.)
- 2013-03-14 16:38:15下载
- 积分:1
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huffman
数据结构(严蔚敏版)中哈夫曼树的操作程序源代码(Of data structure (Yan Wei Min version) operating procedures in the source code Huffman tree)
- 2010-05-24 23:19:39下载
- 积分:1
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maze
迷宫求解一般采用“穷举法”,逐一沿顺时针方向查找相邻块(一共四块-东(右)、南(下),西(左)、北(上))是否可通,即该相邻块既是通道块,且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)
- 2013-12-13 17:55:45下载
- 积分:1