▍1. fanzheji
一个反褶积的VC++例子,简单明了,很适合刚刚开始学习信号分析的人(A deconvolution of VC++ Example simple, it is suitable for signal analysis has just begun to study people)
一个反褶积的VC++例子,简单明了,很适合刚刚开始学习信号分析的人(A deconvolution of VC++ Example simple, it is suitable for signal analysis has just begun to study people)
用于启动界面的制作,以及对于词法的分析,很实用的东西(Interface used to start production, as well as for lexical analysis, a very practical things)
调用会出现一个功能界面计算器,通过它你可以来计算一些加减乘除运算.(There will be a function call interface calculator, which you can calculate a number of addition and subtraction to multiplication and division calculations.)
c和c++动态数组的实现.visual studio 2008下编译通过(c and c++ realize dynamic array. visual studio 2008 under the compiler through)
利用PSO粒子群搜索算法,辨识PID参数:Kp,Ki,Kd.结果表明虽然该方法辨识精度不是很高,但是也有一定可信度.(Use english PSO Particle Swarm algorithm, identification of PID parameters: Kp, Ki, Kd. The results show that although the method is not very high recognition accuracy, but it also has a certain credibility.)
针对水轮机调节系统PID参数辨识问题,作者在VC++6.0环境下,使用c语言,编写PID参数参数辨识程序,结果表明,该程序能够辨识出Kp,Ki,Kd三个参数,满足调节系统的误差要求。(Turbine regulating system for PID parameter identification problem, the authors VC++ 6.0 environment, using c language, the preparation of PID parameters of parameter identification procedures, results show that the program can identify Kp, Ki, Kd three parameters to meet conditioning systems error requirements.)
一个C程序:以便在购书籍量超过5本并且购买总额超过500元时,提供15%的折扣。接受用户输入书籍数量及购买总额,并显示最终应付总额。(A C procedure: in order to purchase books in quantity more than 5 and the total amount of the purchase of more than 500 yuan to provide 15 discount. Accept user input and purchase the total number of books and displays the total amount of the final meet.)
用VC操作EXCEL的方法,生成了一个excel表格(EXCEL using VC operation method to generate a excel form)
大量的DOS批处理源代码,功能设计各个方面,对学习很有用(A large number of DOS batch source code, functional design in all aspects of learning useful)
利用FT245BM USB模块做的虚拟示波器,暂时可以达到1M的速率!(FT245BM USB modules make use of a virtual oscilloscope, the time being can achieve a rate of 1M!)
这是一个日期查询系统,它的功能有:判断闰年,查询星期功能。(This is a date inquiry system, its functions are: to determine leap year, query functionality weeks.)
大型CFD源程序DUNS,求威望 介绍: Diagonalized ADI Navier-Stokes (DUNS) Code The DUNS code is a 2d/3d, structured, multi-block, multi-species, unsteady or steady, Navier Stokes fluid dynamics code with the q-omega turbulence model. It is configurable on several different levels allowing you to make the code as general or as efficient as you desire. It has been developed on Linux, Cray, RISC6000 and to a lesser extent SGI and HP architectures. It is written in FORTRAN-77 and C. It has been used primarily as a research code, and because of that, the coding can be at times rather undocumented and unclear.(Large-scale CFD source DUNS, seeking prestige Introduction: Diagonalized ADI Navier-Stokes (DUNS) CodeThe DUNS code is a 2d/3d, structured, multi-block, multi-species, unsteady or steady, Navier Stokes fluid dynamics code with the q- omega turbulence model. It is configurable on several different levels allowing you to make the codeas general or as efficient as you desire. It has been developed on Linux, Cray, RISC6000 and to a lesser extent SGI and HP architectures. It is written in FORTRAN-77 and C. It has been used primarily as a researchcode, and because of that, the coding can be at times rather undocumentedand unclear.)
用matlab仿真实现从一副图像的边缘进行边缘直线拟合(Matlab simulation using an image from the brink of the brink of a straight line to fit)
Netbeans插件开发,实现在线聊天功能(Netbeans Plug-in Development, the realization of online chat)
求标准正态分布,可精确到任意指定小数位。(For standard normal distribution, can be accurate to any specified decimal places.)
编写C程序,随机给出n*n的邻接矩阵,并打印输出邻接矩阵,以及有向图的边的个数,每个顶点的度,并判断该图中是否存在Euler回路: (1)如果为n阶,则随机产生一个n*n的邻接矩阵; (2)输出邻接矩阵,边的个数,每个顶点的度以及图中是否存在Euler回路。 这个题目涉及到了两个主要的知识点,一个是数据结构中的有向图的邻接矩阵的创建,还有就是离散数学中的Euler回路的判定定理。(The preparation of C procedures, were randomly given n* n s adjacency matrix and adjacency matrix printouts, as well as to map the number of edges, each vertex degrees, and determine the existence of the map Euler circuit: (1) If for n-order, then randomly generated a n* n adjacency matrix (2) output adjacency matrix, the number of edges, each vertex of degree as well as map the existence of Euler circuit. This topic relates to two main points of knowledge, a data structure of digraph adjacency matrix of creation, there is discrete mathematics in the loop to determine Euler theorem.)
C++递归调用,4个整数用四则运算算24(C++ Recursive calls, with four integer arithmetic operator 24)